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Nimfa-mama [501]

3 years ago

6

A steel pipe in the shape of a right circular cylinder is used for drainage under a road. The length of the pipe is 12 feet, and

its diameter is 36 inches. The pipe is open at both ends. A wire screen in the shape of a square is attached at one end of the pipe to allow water to flow through but to keep animals from getting inside the pipe. The length of the diagonals of the screen are equal to the diameter of the pipe. The figure represents the placement of the screen at the end of the pipe.

1 answer:

Vesnalui [34]3 years ago

5 0

Answer:

C

Step-by-step explanation:

since the diagonal of the square is 36 inches:

by pythagoras:

c--> side

c^2 + c^2 = 36^2

2c^2 = 1296

c^2 = 648

c = 25.46 inches

thus the perimeter:

4c = 4 x 25.46 = 102

and the area:

c^2 = 648

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Answer:

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Step-by-step explanation:

$y=x^2-6x+3$

This is written in the standard form of a quadratic function:

$y=ax^2+bx+c$

where:

ax² → quadratic term
bx → linear term
c → constant

You need to convert this to vertex form:

$y=a(x-h)^2+k$

where:

(h,k) → vertex

To find the vertex form, you need to find the vertex. For this, use the equation for axis of symmetry, since this line passes through the vertex:

$x=-\frac{b}{2a}$

Using your original equation, identify the a, b, and c terms:

$a=1\\\\b=-6\\\\c=3$

Insert the known values into the equation:

$x=-\frac{(-6)}{2(1)}$

Simplify. Two negatives make a positive:

$x=\frac{6}{2} =3$

X is equal to 3 (3,y). Insert the value of x into the standard form equation and solve for y:

$y=3^2-6(3)+3$

Simplify using PEMDAS:

$y=9-18+3\\\\y=-9+3\\\\y=-6$

The value of y is -6 (3,-6). Insert these values into the vertex form:

$(3_{h},-6_{k})\\\\y=a(x-3)^2+(-6)$

Insert the value of a and simplify:

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:Done

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How do you know if two lines are parallel?

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LenaWriter [7]

Answer:

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Step-by-step explanation:

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