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lyudmila [28]
3 years ago
5

A WATER WAY CONTAINS 10.3 MILIGRAMS OF IMPURITY PER GALLON OF WATER.HOW MANY MICROGRAMS OF IMPURITY ARE PRESENT PER LITER OF WAT

ER.
1 MG= 1000 MICROGRAMS
1 GAL=3.79 LITERS
Chemistry
1 answer:
Trava [24]3 years ago
6 0

I Gallon = 3.785 L 1 Mg = 1 mg gallon 3.785L. 3. The recommended adult dose of Elixophyllin®, a drug used to treat asthma, is 6.00 mg/kg of body mass. Calculate the dose in milligrams for a 112 lb person. (o oo Kg | K9 6.oong 112 15 = 3 04.7 - 3 2.20515 2.20516 my k.

Hope this answer will help you.

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3 years ago
What type of wave do the contractions of the snake muscles make as the snake moves forward
S_A_V [24]
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3 years ago
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3 years ago
10) How many grams are there in 1.00 x 10^24 molecules of BC13?
lana66690 [7]

194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

Explanation:

In order to convert the given number of molecules of BCl₃ to grams, first we have to convert the molecules to moles.

It is known that 1 moles of any element has 6.022×10²³ molecules.

Then 1 molecule will have \frac{1}{6.022*10^{23} } moles.

So 1*10^{24} molecules = \frac{1*10^{24} }{6.022*10^{23} } =1.66 moles

Thus, 1.66 moles are included in BCl₃.

Then in order to convert it from moles to grams, we have to multiply it with the molecular mass of the compound.

As it is known as 1 mole contains molecular mass of the compound.

As the molecular mass of BCl₃ will be

Molecular mass of BCl_{3}= Mass of Boron + (3*Mass of chlorine)

Mass of boron is 10.811 g and the mass of chlorine is 35.453 g.

Molar mass of BCl₃ = 10.811+(3×35.453)=117.17 g.

grams of BCl_{3}=Molar mass of BCl_{3}*Number of moles

grams of BCl_{3}=117.17*1.66=194.5 g

So, 194.5 g of BCl₃ is present in 1 × 10²⁴ molecules of BCl₃.

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3 years ago
Does Ag metal reacts with NaOH​
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