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lyudmila [28]
2 years ago
5

A WATER WAY CONTAINS 10.3 MILIGRAMS OF IMPURITY PER GALLON OF WATER.HOW MANY MICROGRAMS OF IMPURITY ARE PRESENT PER LITER OF WAT

ER.
1 MG= 1000 MICROGRAMS
1 GAL=3.79 LITERS
Chemistry
1 answer:
Trava [24]2 years ago
6 0

I Gallon = 3.785 L 1 Mg = 1 mg gallon 3.785L. 3. The recommended adult dose of Elixophyllin®, a drug used to treat asthma, is 6.00 mg/kg of body mass. Calculate the dose in milligrams for a 112 lb person. (o oo Kg | K9 6.oong 112 15 = 3 04.7 - 3 2.20515 2.20516 my k.

Hope this answer will help you.

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B

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Bacteria living in the soil are dependent upon which of the following abiotic factors?
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Soil temperature and <span>water content</span>
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Three players (A, B and C) shoot three arrows at a target
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3 years ago
Write the net ionic equation for the reaction that occurs when equal volumes of 0.546 M aqueous acetylsalicylic acid (aspirin) a
Tatiana [17]

Answer:

C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to figure out the required net ionic equation by firstly writing out the complete molecular equation between aspirin and sodium acetate:

C_9H_8O_4+NaC_2H_3O_2\rightarrow C_2H_4O_2+NaC_9H_7O_4

Whereas acetic acid and sodium acetylsalicylate are formed. Now, we write the complete ionic equation whereby sodium acetate and sodium acetylsalicylate are ionized because they are salts yet neither aspirin nor acetic acid are ionized as they are weak acids:

C_9H_8O_4+Na^++C_2H_3O_2^-\rightarrow C_2H_4O_2+Na^++C_9H_7O_4^-

Finally, for the net ionic equation we cancel out the sodium spectator ions to obtain:

C_9H_8O_4+C_2H_3O_2^-\rightarrow C_2H_4O_2+C_9H_7O_4^-

Regards!

7 0
2 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
3 years ago
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