Answer:
Mg
Explanation:
Magnesium has a valency of +2
Answer:
The correct option is e.
Explanation:
p-value is the probability value for a given statistical model, the probability that, when the null hypothesis is true.
For two two samples the formula of test statistics is

where,
is sample mean
is population mean.
is standard deviation.
n is sample size.
Variance is the square of standard deviation.
It means variance, mean, numbers of samples is used in calculation of p-value.
Degree of freedom define the shape of the t-distribution that your t-test uses to calculate the p-value.

p-value of a statistical test depends on all of the following, except median.
Therefore the correct option is e.
Note that it says oxygen "gas"
So you need the atomic mass of oxygen gas
Look at your periodic table, you'll see 15.9994 under oxygen
Oxygen gas has a formula of O2 therefore,
(15.9994) times 2= Oxygen gas atomic mass=31.9988
Mol= Mass/Atomic Mass
=62.3 g/ 31.9988 g/mol = 1.95 mol
now look at the ratio of C2H6 and O2, notice there is an invisible number beside each of them, at that "invisible number" is =1
1 C2H6 + 1 O2 -> products
this means that for 1 mol of C2H6, 1 mol of O2 has to react with it
Thus as we have 1.95 moles of O2, we need 1.95 moles of C2H6
Because when you compress something, you compress an object to either tighten or get it smaller.
Since liquids have no shape of their own, you cannot squeeze or squish it to tighten/get it smaller.
Hopes this helps <span />
Answer:
the reaction is spontaneous at T > 2900 K
Explanation:
∴ ΔH = +120 KJ
∴ ΔS = (-42 J/K)*(KJ/1000 J) = -0.042 KJ/K
∴ ΔG < 0 ⇒ the reaction is spontaneous
⇒ at T = 2900 K:
⇒ ΔG = 120 - (2900)(-0.042) = 120 - 121.8 = - 1.8 KJ < 0