How many moles of sodium atoms in 255 grams of na2so4

1 answer:

5 0

$M_{Na_{2}SO_{4}}=142\frac{g}{mol}\\
m=255g\\\\
n=\frac{m}{M}=\frac{255g}{142\frac{g}{mol}}\approx1,8mol\\\\
1,8mol*2=3,6mol \ of \ sodium \ atoms$

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