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vekshin1
3 years ago
7

What is the formal charge on the hydrogen atom in hf?

Chemistry
2 answers:
stepladder [879]3 years ago
4 0

The formal charge of H = +1, because F in compounds can have only -1.

REY [17]3 years ago
4 0

Answer:

The formal charge on H atom in HF = 0

Explanation:

Formal charge is the charge on an atom when all the chemical bonds that are formed by that atom are formed by equal sharing of electrons.

<u>The formal charge of an atom is given by the equation:</u>

Formal charge = [Total number of valence electrons in the ground state (n)] - [Number of non-bonding valence electrons on atom in a molecule (N)] - [Number of shared or bonding electrons (B) ÷ 2]

<u>To find out the formal charge on hydrogen (H) atom in H-F molecule:</u>

For H atom in ground state: n = 1

For H atom in H-F molecule: N = 0 and B = 2

Since, Formal charge = n - N - (B ÷ 2)

So, The formal charge on H atom in HF = 1 - 0 - (2÷ 2) = 1 - 1 = 0

<em><u>Therefore, the formal charge on H atom in HF = 0</u></em>

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What is the same for all of the drilling sites we examined?
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Answer:

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When you have finished adding the necessary amount of NaOH to your beaker, what color will the litmus paper turn?
Svetllana [295]

<u>Answer:</u> The red litmus paper turns blue on dipping in NaOH solution.

<u>Explanation:</u>

Litmus paper is the indicator that detects the nature of the solution, whether it is acidic or basic.

There are 2 types of litmus paper:

  • <u>Red litmus paper:</u> This paper will turn blue if it is dipped in basic solution and will remain as such if it is dipped in acidic solution.
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NaOH is a strong base, so when a red litmus paper is dipped in the beaker having necessary amount of NaOH, the red litmus paper turns into blue.

7 0
4 years ago
g Five calcite, CaCO3 (MW 100.085 g/mol), samples of equal mass have a total mass of 12.3±0.1 g. What is the absolute uncertaint
diamong [38]

Answer:

The value  is   L  =  0.985 \pm 0.00801 \  g

Explanation:

From the question we are told that

  The  molar mass of CaCO_3 is  MW  =  100.085 \  g/mol

   The  total mass is  m_g  = 12.3 \ g

   The uncertainty of the total mass is \Delta g  = 0.1

Generally the molar weight of calcium is M_c  =  40 g/mol

 The percentage of calcium in calcite is mathematically represented as

          C =  \frac{40.07}{100.085} * 100

          C =  40.03 \%

Generally the mass of each sample is mathematically represented as

     m=  \frac{m_g}{5}

     m=  \frac{12.3}{5}

     m= 2.46 \  g

Generally mass of calcium present in a single sample is mathematically represented as

        m_c = 2.46 *  \frac{40.04}{100}

       m_c = 0.985 \  g

The  uncertainty of  mass of a single sample is mathematically represented as

      k  =  \frac{\Delta g }{5}

        k  =  \frac{0.1 }{5}

       k  =  0.02\  g

The  uncertainty of  mass of calcium in a single sample is mathematically represent

         G  =  \frac{0.02 *  40.04}{ 100}

          G  =  0.00801 \  g

Generally the average mass of calcium in each sample is  

          L  =  0.985 \pm 0.00801

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Explanation: bcuz I said

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