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3 years ago

What is the formal charge on the hydrogen atom in hf?

Chemistry

2 answers:

stepladder [879]3 years ago

4 0

The formal charge of H = +1, because F in compounds can have only -1.

REY [17]3 years ago

4 0

Answer:

The formal charge on H atom in HF = 0

Explanation:

Formal charge is the charge on an atom when all the chemical bonds that are formed by that atom are formed by equal sharing of electrons.

The formal charge of an atom is given by the equation:

Formal charge = [Total number of valence electrons in the ground state (n)] - [Number of non-bonding valence electrons on atom in a molecule (N)] - [Number of shared or bonding electrons (B) ÷ 2]

To find out the formal charge on hydrogen (H) atom in H-F molecule:

For H atom in ground state: n = 1

For H atom in H-F molecule: N = 0 and B = 2

Since, Formal charge = n - N - (B ÷ 2)

So, The formal charge on H atom in HF = 1 - 0 - (2÷ 2) = 1 - 1 = 0

Therefore, the formal charge on H atom in HF = 0

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4 years ago

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3 years ago

Why do scientists look for patterns in the world?

White raven [17]

So they can predict what happens next

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3 years ago

Read 2 more answers

Help me for number 8 and 9

krek1111 [17]

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4 years ago

Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 1.731.

Amanda [17]

Answer:

The answer to your question is letter c) 6.09 g of sodium and 9.38 g of chlorine.

Explanation:

This problem is solve using rule of three

We know that the proportion Sodium to Chloride is 1 to 1 in sodium chloride, so we have to look for this proportion in the options

AM Sodium = 23 g

AM Chlorine = 35.5 g

Sodium Chlorine

23 g ---------------- 1 mol 35.5 g -------------- 1 mol

1713.73g ------------- x 2666.6 g ------------- x

x = 1713.73/23 = 74.51 x = 2666.6/35.5 = 75.12

These values are very similar, we have to look for the proportion in the options

a) 6.09g of sodium = 0.26 mol

4,87 g of chlorine = 0.14 mol These numbers are not very similar

b) We have 0.26 mol of Na

0.037 mol of Cl This is not the answer

c) We have 0.26 mol of Na

0.26 mol of Cl These numbers are the same, the proportion is 1:1, this is the answer

d) We have 0.26 mol of Na

0.36 mol of Cl This is not the answer

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3 years ago