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timurjin [86]
2 years ago
14

I need help on this math problem

Mathematics
1 answer:
kakasveta [241]2 years ago
4 0

Answer:

y= −1/2x + 3/4

Step-by-step explanation:

Write in slope-intercept form, y=mx +b.

Problem: 6x+12y=9

Hopefully this helps you!

Still stuck? Get 1-on-1 help from an expert tutor now.

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Help with functions right quick? :) please
-Dominant- [34]
The answer is:  [B]:  -4  .
_____________________________
Here is the problem:
_____________________
 "Find f(3)."
_______________________
    f(x) = \left \{ {x + 5 ;   if  x \ \textless \ -2 ;  \atop {-4; if x  \geq -2 ;}} \right. ;
______________________________________
Since we are asked to find:  " f(3)" ;  we consider the number, "3", which is GREATER THAN OR EQUAL TO "-2" ; (that is,  " 3 \geq -2" ;
 and f(x) = -4  if x \geq  -2 . 
_____________________________________________________
So, in this case, f(x) = f(3) =  -4 ; which is: "Answer choice: [B] ".
_____________________________________________________

6 0
4 years ago
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
Calvin has 2 3/4 chapters left in his book he reads 1 3/4 chapters before bed how many chapters dose he have left
Taya2010 [7]
He will have 1 chapter left.
5 0
3 years ago
Read 2 more answers
What is the correct solution to the problem 6 x 3/8?
Setler79 [48]

Answer:

<h2><u><em>9/4 or 2.25</em></u></h2>

Step-by-step explanation:

what is the correct solution to the problem 6 x 3/8?

6 * 3/8 =

semplify

3  * 3/4 =

9/4 or 2.25

5 0
2 years ago
Read 2 more answers
What are the vertices of A'B'C if ABC is dilated by a scale factor of 2?
malfutka [58]

The vertices of A'B'C' if A(0, 10), B(8, 6), C(4, 2) is dilated by a scale factor of 2 are;

  • C. A'(0, 20), B'(16, 12), C'(8, 4)

<h3>Which method can be used to find the vertices of A'B'C'?</h3>

Given that triangle ABC is dilated by a scale factor of 2, we have;

A'B' = 2 × AB

A'C' = 2 × AC

B'C' = 2 × BC

Length of AB = √((8-0)^2 + (6-10)^2) = 4•√5

Length of AC = √((4-0)^2 + (2-10)^2) = 4•√5

Length of BC = √((8-4)^2 + (6-2)^2) = 4•√2

By multiplying the given coordinates by the scale factor, we have;

A' = 2 × (0, 10) = (0, 20)

B' = 2 × (8, 6) = (16, 12)

C' = 2 × (4, 2) = (8, 4)

A'B' = √((16-0)^2 + (12-20)^2) = 8•√5

A'C' = √((8-0)^2 + (4-20)^2) = 8•√5

B'C' = √((16-8)^2 + (12-4)^2) = 8•√2

Therefore when we have;

A'(0, 20), B'(16, 12), C'(8, 4), we get;

  • A'B' = 2 × AB
  1. A'C' = 2 × AC
  2. B'C' = 2 × BC

The correct option is therefore;

  • C. A'(0, 20), B'(16, 12), C'(8, 4)

Learn more about finding the distance between points on the coordinate plane here:

brainly.com/question/7243416

#SPJ1

5 0
2 years ago
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