Question

In an pot of water you have 2.5 L at 25oC. How much energy will be needed to heat up the water to 100oC

Answer 1

Answer:

784500 Joules

Explanation:

To start, you will need an equation to find the change in energy. This can be found by using $Q = mCT$ or by using integrated heat capacities.

to find the mass of water,

$2.5L * 1kg/L = 2.5 kg water$

1kg/L is the density of water.

Then, $Q = 2.5kg*4.184J/gC*(100-25)$

Notice that all of the units do not cancel out properly, so some unit conversions are needed to find the correct answer.