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LUCKY_DIMON [66]
3 years ago
14

Please Help thank you

Chemistry
1 answer:
Harlamova29_29 [7]3 years ago
4 0

I suppose because of the fact that the relative humidity is taking away your heat and making you feel cool, I think that you would feel cooler than someone who was dry.

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If the Bunsen burner gave a luminous flame and some soot was deposited on
Harlamova29_29 [7]

Explanation:

If bunsen burner gave a luminous flame then there will deposition of soot at the bottom of the test tube which is actually pure carbon.

This deposition of soot actually depicts that there is incomplete combustion reaction that has taken place.

Also, the deposition of soot will provide a limited supply of oxygen to the reaction that has been calculated.

Therefore, in order to avoid any formation of soot it is advisable to adjust the burner flame till it produces a blue flame.

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How are isotopes of the same element alike? different?
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Calculate the vapor pressure at 25°C of a solution containing 55.3 g ethylene glycol (HOCH2CH2OH) and 285.2 g water. The vapor p
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Vapor pressure of solution = 23.9 Torr

Explanation:

Let's apply the colligative poperty of vapor pressure to solve this:

ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent - Vapor pressure of solution

We have solvent and solute mass, so let's find out the moles of each.

55.3 g / 62 g/mol = 0.89 moles

285.2 g / 18 g/mol = 15.84 moles

Let's determine the mole fraction of ethylene glycol.

Mole fraction = Moles of ethylene glyco / Total moles

0.89 moles / (0.89 + 15.84) = 0.053

25.3 Torr - Vapor pressure of solution = 25.3 Torr . 0.053

Vapor pressure of solution = 25.3 Torr . 0.053 - 25.3 Torr

Vapor pressure of solution = 23.9 Torr

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