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fenix001 [56]
2 years ago
5

Solve for linear inequality of x - 1 ≥ 4 + x​

Mathematics
1 answer:
defon2 years ago
8 0

\huge\bf{ANSWER:}

\huge\mathrm{No\:solution.}\checkmark

\huge\bf{SOLUTION}:

Hey there, hope you are having a wonderful day! :)

Let's solve this inequality.

First of all, let's move all the numbers to the right, using the \bf{\underline{opposite\:\:operation\:}:

\longmapsto\sf{x-1\geq 4+x

\longmapsto\sf{x\geq 4+x+1

\longmapsto\sf{x\geq x+5

Now, let's move the variables to the left:

\longmapsto\sf{x-x\geq 5

\longmapsto\sf{0\geq 5

Now, as you can see, we ended up with a false statement. 0 is NOT greater than 5.

Thus, there are no values of x that make the inequality true, and the inequality  has

\bold{No\:solutions.}

Hope you find it helpful.

Feel free to ask if you have any doubts.

\bf{-MistySparkles^**^*

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3 years ago
Solve the quadratic equation by completing the square.<br> x²–2x-12=0
inn [45]

Answer:

(x-1)^2-13=0

x = \sqrt{13}+1

Step-by-step explanation:

Completing the square is a method of rewriting a quadratic equation in the standard form such that it is in vertex form. The first step is to group the linear and quadratic terms, then factor out the coefficient of the quadratic term. After doing so, complete the square, add a value such that the linear and quadratic terms form a perfect square trinomial. Do not forget to balance the equation. The final step is to simplify.

x^2-2x-12=0

Group,

(x^2-2x)-12=0

Complete the square,

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Simplify,

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Now solve the equation using inverse operations,

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