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Stella [2.4K]
4 years ago
12

The difference between the third and fourth ionization energies of scandium is much larger than the difference between the third

and fourth ionization energies of titanium. why?
Physics
1 answer:
Maru [420]4 years ago
5 0

This is because removing three electrons means third ionization energy would leave scandium with a full valence shell that is 3s²3p⁶ and removing a fourth electron would begin to remove electrons from a full valence shell which is very energetically not favorable.

<span>Removing a third and fourth electron from titanium is bringing Ti closer and closer to having an empty 4th energy level and a completely full 3rd energy level. Removing the 4th electron would be very energetically favorable because it would result in a full valence shell</span>.

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A 2.50-m segment of wire carries 1000 A current and feels a 4.00-N repulsive force from a parallel wire 5.00 cm away. What is th
Stolb23 [73]

Answer:

The current is  I_b  =  400 \ A

Explanation:

From the question we are told that

    The  length of the segment is  l  =  2.50  \  m

     The current is  I_a  =  1000 \ A

     The force felt is  F  =  4.0 \  N

        The distance of the second wire is  d =  5.0 \ cm  = 0.05 \  m

Generally the current on the second wire is mathematically represented as

        I_b  =  \frac{2 \pi * r * F }{ l *  \mu_o  *  I_a }

Here  \mu_o is the permeability of free space with value  \mu_o =  4 \pi * 10^{-7} \ N/A^2

=>      I_b  =  \frac{2 * 3.142  *  0.05 *  4 }{ 2.50  *  4\pi *10^{-7}  * 1000 }

=>      I_b  =  400 \ A

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Answer:

1. What type of wave is sound?

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