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Strike441 [17]
3 years ago
14

A car starting at rest accelerates to a speed of 6miles/hr in 5 sec what is the average acceleration

Physics
2 answers:
maw [93]3 years ago
7 0
That look very confusing
Luden [163]3 years ago
5 0

Answer:

1.2 mi/hr/sec

Explanation:

<em>a = Vf - Vi / t (formula)</em>

-----------------------------------

     6mi/hr - 0 mi/hr        6 mi/hr

a = ____________ =    _______ = 1.2 mi/hr/sec

              5 sec                 5 sec

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Puck A, of inertia mm, is attached to one end of a string of length ℓℓ , and the other end of the string is attached to a pivot
algol13

Answer:

L_{B} / L_{A} = \frac{5mvl}{mvl}= 5

Explanation:

Find the given attachment

8 0
3 years ago
During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to c
IRINA_888 [86]

During a rodeo, a clown runs 7.7 m north, turns 49.9 degrees east of north, and runs 6.4 m. Then after waiting for the bull to come near, the clown turns due east and runs 19.8 m to exit the arena. The magnitude of the clown’s displacement is 27 m.

<u>Explanation: </u>

As the clown is running in the north direction for about 7.7 m and then he turns 49.9 degrees east of north. In the east of north, he covers a distance of 6.4 m and then turns east to exit the arena after covering a distance of 19.8 m. Let’s have a simple diagram to easily understand the problem.

In first step, the clown runs 7.7 m in north direction, so the image will be  as in fig 1. Then he takes a direction of north east and covers a distance of 6.4 m, so the image will be modified as in fig 2. Then after the bull comes, he turns east and runs 19.8 m to exit the arena, so the image will be as in figure 3.

So, the extension of North line and the East line at a point shown as the dotted line in the above image, forms the total displacement as the hypotenuse of a right angled triangle. The extended dotted lines is nothing but the horizontal and vertical components of the angle 49.9 degree.

By using Pythagoras theorem, the total displacement can be found as

\text { Total displacement }=\sqrt{(o p p)^{2}+(a d j)^{2}}

\text { Distance covered by the clown in east direction }=(6.4 \times \cos 49.9)+19.8=23.9 \mathrm{m}

Similarly, the adjacent side of this imaginary triangle is the distance covered by the clown in the North direction.

\text { Distance covered by the clown in north direction }=6.4 \sin 49.9+7.7=12.6 \mathrm{m}

Thus, the total displacement covered by the clown is

\text { Total displacement }=\sqrt{(23.9)^{2}+(12.6)^{2}}=\sqrt{571.21+158.76}=\sqrt{729.97}=27 \mathrm{m}

Thus, the total displacement by the clown is 27 m.

5 0
3 years ago
Lifetime activities are activities that can be __________.
Usimov [2.4K]

Answer:

A

Explanation:

Enjoyed for many years or decades.

6 0
3 years ago
Read 2 more answers
What is inertia?
EleoNora [17]
Answer: C. The tendency of an object to maintain its state of motion.

Explanation: Newton’s first law: If a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
4 0
3 years ago
A man pushed a cabinet with a force of 200N. What is the mass of the cabinet that accelerates 4 m/s/s?​
ELEN [110]

Answer:

\boxed {\boxed {\sf 50 \ kg}}

Explanation:

We are asked to find the mass of a cabinet, given the force and acceleration. According to Newton's Second Law of Motion, force is the product of mass and acceleration. The formula for this is:

F= m \times a

The force is 200 Newtons, but we should convert the units to make unit cancellation easier. 1 Newton is equal to 1 kilogram meter per second squared, so the force of 200 Newtons is 200 kilogram meters per second squared.

The mass is unknown and the acceleration is 4 meters per second per second or 4 meters per second squared.

  • F= 200 kg*m/s²
  • a= 4 m/s²

Substitute the values into the formula.

200 \ kg *m/s^2 = m \times 4 \ m/s^2

We are solving for the mass, m, so we must isolate the variable. It is being multiplied by 4 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 4 m/s²

\frac {200 \ kg *m/s^2}{4 \ m/s^2}= \frac{m \times 4\ m/s^2}{4 \ m/s^2}

\frac {200 \ kg *m/s^2}{4 \ m/s^2} =m

The units of meters per second squared cancel.

\frac {200 \ kg }{4 }=m

50 \ kg =m

The mass of the cabinet is <u>50 kilograms.</u>

5 0
3 years ago
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