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erik [133]
3 years ago
14

A hill that has a 15.5% grade is one that rises 15.5 m vertically for every 100.0 m of distance in the horizontal direction. At

what angle is such a hill inclined above the horizontal
Physics
1 answer:
Andreas93 [3]2 years ago
6 0

The angle of incline of the hill above the horizontal is 8.81°.

Since the hill has a 15.5% grade is one that rises 15.5 m vertically for every 100.0 m of distance in the horizontal direction.

<h3>Tangent of the angle of the incline of the hill,</h3>

The tangent of the angle of the incline of the hill, Ф is

tanФ = vertical rise/horizontal distance = grade of hill

Now, the vertical rise = 15.5 m and the horizontal distance = 100.0 m

So, substituting the values of the variables into the equation, we have

tanФ = vertical rise/horizontal run

tanФ = 15.5 m/100.0 m

tanФ = 0.155

<h3>Angle of incline of the hill</h3>

Taking inverse tan of both sides, we have

Ф = tan⁻¹(0.155)

Ф = 8.81°

So, the angle of incline of the hill above the horizontal is 8.81°.

Learn more about angle of incline of a hill here:

brainly.com/question/10056962

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Answer:

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4 years ago
When a fish expands its air bladder, the density of the fish
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<h2>Answer: decreases</h2>

Every substance, body or material has mass and volume, however the mass of different substances occupy different volumes.

This is where density  D  appears as a  physical characteristic property of matter that establishes a relationship between the mass  m of a body or substance and the volume  V it occupies.

D=\frac{m}{V}

So, according to this equation, the density is inversely ptoportional to the volume:

If the volume increases, the density decreases.

This is what a fish does to have buoyancy, since the density of a body is related to its buoyancy:

A body will float on another fluid if its density is lower.

<h2>This is what the fish does when it expands its air bladder, incrementing its volume, hence decreasing its density.</h2>

8 0
3 years ago
A car starts from rest, speeds up with constant acceleration, and travels 400 meters in 10 seconds. What was the acceleration of
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Answer:

Acceleration of the car will be a=8m/sec^2

Explanation:

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We have to find the acceleration of the car

From second equation of motion we know that s=ut+\frac{1}{2}at^2

So 400=0\times 10+\frac{1}{2}\times a\times 10^2

a=8m/sec^2

So acceleration of the car will be a=8m/sec^2

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Which of the following represents a covalent compound?<br> a. BeF2<br> b. KF<br> C. PCIE<br> d. Ti
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The diagram is labelled to DRAW the RESULTANT wave and LABEL the areas of interference with CI, DI and/or points of TDI.

<h3>What is refraction?</h3>

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Learn more about refraction.

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