Answer:
The speed of the sap flowing in the vessel is 1.90 mm/s
Explanation:
Given:
The rate of water loss, Q = 3 × 10 ⁻⁸ m³/s
Number of vessels contained, n = 2000
Diameter of the vessel, D = 100 Mu m
thus, the radius of the vessel, r = 50 × 10⁻⁶ m
Now, the rate of flow is given as:
Q = AV .............(1)
where, A is the area of the cross-section
V is the velocity
Total area, A = n × (πr²)
substituting the values in the equation (1), we get
3 × 10 ⁻⁸ m³/s = [2000 × (π × (50 × 10⁻⁶)²)] × V
or
V = 1.909 × 10⁻³ m/s or 1.90 mm/s
Hence, the speed of the sap flowing in the vessel is 1.90 mm/s
