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2 years ago

Can someone please help me? :(

Mathematics

2 answers:

Sergeu [11.5K]2 years ago

7 0

Answer:

A. -1 ≤ x < 2

Step-by-step explanation:

It shows on the number line.

viktelen [127]2 years ago

5 0

Answer:

Step-by-step explanation:

i dont have a step by step but there you go

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Population lottery numbers: 56, 42, 19, 8, 24, 13 find the total number of samples of size 4 that can be drawn from this populat

statuscvo [17]

Answer:

The correct answer is there are 15 samples each of size 4 to choose from the population and the population mean is 27.

Step-by-step explanation:

Total number of lottery tickets = 6

Number of samples of size 4 that can be drawn from this population of 6 lottery numbers are = $\left[\begin{array}{ccc}6\\4\end{array}\right]$ = 15.

Now the population mean is given by $\frac{1}{n}$ × ∑ x , where n is the number of lottery tickets and ∑ x is the sum of the lottery numbers.

Summation of the lottery ticket numbers is 162

Thus the population mean is given by $\frac{162}{6}$ = 27.

8 0

3 years ago

A state end-of-grade exam in American History is a multiple-choice test that has 50 questions with 4 answer choices for each que

Assoli18 [71]

Answer:

Q1) The student has a 0.01% probability of passing the test.

Q2) She has a 99.91% probability of passing in the test.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he gets it correct, or he gets it wrong. So we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

Question 1.

There are 50 questions, so $n = 50$ .

The student is going to guess each question, so he has a $\pi = \frac{1}{4} = 0.25$ probability of getting it right.

He needs to get at least 25 question right.

So we need to find $P(X \geq 25)$ .

Using a binomial probability calculator, with $n = 50$ and $\pi = 0.25$ we get that $P(X \geq 25) = 0.0001$ .

This means that the student has a 0.01% probability of passing the test.

Question 2.

Now, we need to find $P(X \geq 25)$ with $\pi = 0.70$ . So $P(X \geq 25) = 0.9991$

She has a 99.91% probability of passing in the test.

7 0

3 years ago

Read 2 more answers

A rectangular mat has a length of 12 in. and a width of 4 in. Drawn on the mat are three circles. Each circle has a radius of 2

pickupchik [31]

$|\Omega|=4\cdot12=48\\ |A|=3\cdot3.14\cdot2^2=37.68\\\\ P(A)=\dfrac{37.68}{48}\approx0.79$

7 0

3 years ago

Find a formula for the distance from the point P(x,y,z) to each of the following planes. a. Find the distance from P(x,y,z) to

BARSIC [14]

Answer:

Distance to the xy-plane = |z|

Distance to the yz-plane = |x|

Distance to the xz-plane = |y|

Step-by-step explanation:

The distance from P(x,y,z) to the xy-plane is by definition the magnitude of the vector that goes from the perpendicular projection of P over the xy-plane to the point P, which is exactly the magnitude of the vector (0,0,z) = |z| the absolute value of z

Similarly, the distance from P to the yz-plane is |x| and the distance from P to the xz-plane is |y|

Distance to the xy-plane = |z|

Distance to the yz-plane = |x|

Distance to the xz-plane = |y|

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3 years ago

-3 (5-x) > -4x-7+10x

Anastaziya [24]

Answer:

-8/3

Step-by-step explanation:

8 0

3 years ago