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ad-work [718]
3 years ago
12

Which ordered pair is a solution to the system of equations?

Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

  • See below

Step-by-step explanation:

<u>Given system:</u>

  • 2x - y = - 2
  • 15x - 2y = - 7

<u>Solve by elimination, multiply the first equation by - 2 and add up the equations:</u>

  • -2(2x - y) + 15x - 2y = - 2(- 2) - 7
  • -4x + 2y + 15x - 2y = 4 - 7
  • 11x = - 3
  • x = - 3/11

<u>Find the value of y:</u>

  • 2( - 3/11) - y = - 2
  • -6/11 - y = - 2
  • y = 2 - 6/11
  • y = 1/11

<u>Solution is:</u>

  • ( - 3/11, 1/11)
  • <em>None of the answer choices is matching this solution. Something must be wrong with the given equations.</em>
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Decide whether the pair of ratios form a proportion 15/12=4.5/3.6
Hitman42 [59]

Answer: Yes they form a proportion. The given equation is a true equation.

==========================================

Explanation:

The idea is that if we have

a/b = c/d

then that it is the same as

a*d = b*c

This is known as cross multiplication. We'll use this rule to get

15/12 = 4.5/3.6

15*3.6 = 12*4.5

54 = 54

We got the same value on both sides, meaning that the last equation is true. Consequently, it means the first equation is true as well (all three equations are true).

--------

You could also use your calculator to see that

15/12 = 1.25

4.5/3.6 = 1.25

showing that 15/12 = 4.5/3.6 is a true equation and the ratios form a proportion.

4 0
3 years ago
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svp [43]

Answer:

c

Step-by-step explanation:

yes c

4 0
3 years ago
Each big square below represents one whole.
tatyana61 [14]

Answer:

45 percent /100 percent

4 0
3 years ago
PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK
dem82 [27]

Answer:

\huge\boxed{9}

Step-by-step explanation:

\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}

Rule of exponents a^0 = 1 , 1/a^m = a^{-m}

=> \sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}

=> \sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}

Combining same bases

=> \sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}

When bases are same , powers are to be added

=> \sf 2 ^{-16-12+28} * 3^{10-8}

=> \sf 2^{-28+28} * 3^2

=> \sf 2^0 * 3^2

=> \sf 3^2

=> 9

8 0
3 years ago
4^3-(24divided6)+8=?
Oksi-84 [34.3K]

Answer:

68

Step-by-step explanation:

4^3-(24÷6)+8

4³-(4)+8= <em>68</em>

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