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ad-work [718]
3 years ago
15

Workout the lowest integer

Mathematics
1 answer:
V125BC [204]3 years ago
5 0

Answer:

x ≥ 9/2

Step-by-step explanation:

5x - 2 ≥  3x + 7

2x ≥ 9

x ≥ 9/2

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Nico is saving money for his college education. He invests some money at 9% and 800 less than that amount at 6%. The investments
vampirchik [111]

Answer:

$1800 at 9% and $1000 at 6%

Step-by-step explanation:

Not needed

5 0
3 years ago
Help ill give you Brainliesttt ‼️‼️‼️‼️‼️‼️
Lesechka [4]

Answer:

Step-by-step explanation:

+ we take t- number of tickets and each ticket cost $7.

So t is too the number of people who buy tickets, then

0\leq t\leq 200

A) We can calculate the amount of money: M= 7t where 0\leq t\leq 200

B) The domain for t is 0\leq t\leq 200, t is an integer.

C) The range for the amount M:

0*7\leq M\leq 200*7\\0\leq M\leq 1400

5 0
3 years ago
Find a particular solution to the nonhomogeneous differential equation y′′+4y=cos(2x)+sin(2x).
I am Lyosha [343]
Take the homogeneous part and find the roots to the characteristic equation:

y''+4y=0\implies r^2+4=0\implies r=\pm2i

This means the characteristic solution is y_c=C_1\cos2x+C_2\sin2x.

Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form y_p=ax\cos2x+bx\sin2x. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.

With y_1=\cos2x and y_2=\sin2x, you're looking for a particular solution of the form y_p=u_1y_1+u_2y_2. The functions u_i satisfy

u_1=\displaystyle-\int\frac{y_2(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\int\frac{y_1(\cos2x+\sin2x)}{W(y_1,y_2)}\,\mathrm dx

where W(y_1,y_2) is the Wronskian determinant of the two characteristic solutions.

W(\cos2x,\sin2x)=\begin{bmatrix}\cos2x&\sin2x\\-2\cos2x&2\sin2x\end{vmatrix}=2

So you have

u_1=\displaystyle-\frac12\int(\sin2x(\cos2x+\sin2x))\,\mathrm dx
u_1=-\dfrac x4+\dfrac18\cos^22x+\dfrac1{16}\sin4x

u_2=\displaystyle\frac12\int(\cos2x(\cos2x+\sin2x))\,\mathrm dx
u_2=\dfrac x4-\dfrac18\cos^22x+\dfrac1{16}\sin4x

So you end up with a solution

u_1y_1+u_2y_2=\dfrac18\cos2x-\dfrac14x\cos2x+\dfrac14x\sin2x

but since \cos2x is already accounted for in the characteristic solution, the particular solution is then

y_p=-\dfrac14x\cos2x+\dfrac14x\sin2x

so that the general solution is

y=C_1\cos2x+C_2\sin2x-\dfrac14x\cos2x+\dfrac14x\sin2x
7 0
3 years ago
Pls help me plssssssssss
MariettaO [177]

Step-by-step explanation:

what type of help u want......

7 0
3 years ago
A {(2,7), (2,8), (3,8)}
Aleksandr [31]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
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