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bazaltina [42]
2 years ago
6

Your cellphone company charges a $18 monthly fee, plus $0.11 per minute of talk time. One month your cell phone bill was $70.80.

How many minutes did you spend talking on the phone that month?
Mathematics
2 answers:
Eduardwww [97]2 years ago
8 0

Answer:

480 minutes

Step-by-step explanation:

We can write this relationship as y=0.11x+18 and then solve for x when y=70.80:

y=0.11x+18\\\\70.80=0.11x+18\\\\52.80=0.11x\\\\480=x

Therefore, you spent 480 minutes talking.

NemiM [27]2 years ago
5 0

Answer:

480 minutes would be the answer

Step-by-step explanation:

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Answer:

1 (6/6)

Step-by-step explanation:

because 1/3 will turn into 2/6 so when you add them it will be 6/6 :)

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If the ball cost 10 cents and the bat costs $1.00 more than the ball, then the bat would cost $1.10 for a grand total of $1.20. The correct answer to this problem is that the ball costs 5 cents and the bat costs — at a dollar more — $1.05 for a grand total of $1.10.

'Now give me brainiest

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3 years ago
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525/4 ÷ 35/4 need the answer quick​
dalvyx [7]

Answer:

15

Step-by-step explanation:

525/4 ÷ 35/4

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3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
What is the value of a in the equation 3a+b=54 when b=9
klemol [59]
3a + b = 54...when b = 9
3a + 9 = 54
3a = 54 - 9
3a = 45
a = 45/3
a = 15 <===
8 0
3 years ago
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