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Ilya [14]
3 years ago
9

Can absolute value be negative

Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0
No, only the value of what you are finding the absolute value of can be a negative. Examples: |-2|=2 |2|=2
You might be interested in
What is the domain and range of the graph shown?​
marissa [1.9K]

Answer:

[0. infinity)

[0, infinity)

7 0
2 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
For each function below, determine whether or not the function is injective and whether or not the function is surjective. (You
Harlamova29_29 [7]

Answer: First, injective means that for every y, there is only one x such f(x) = y, and surjective means that if f is a function that goes from the set {x} to the set {y}, for every element y in the codomain there is at least one element x in the domain such f(x) = y

(a) f:R----> + R given by f(x) = x2 (i guess you written x^{2})

The function is not injective, because f(-2) = f(2), and is surjective, because the codomain is +R, and x^{2} is always a positive real number.

(b) f:N----> + N given by f(n) = n2  (i guess you written n^{2})

As the naturals have no negative numbers, in this case the function is injective, but isn't surjective, because there is no number that when squared is equal to 5, for example.

(c) f: Zx Z → Z given by f(n, k) = n +k:

here the domain is of the form (n,k) and the function is n +k, so the numbers (z,w) and (w,z) return the same value when evaluated in f, then f is not injective. And is easy to see that f is surjective, because in the sum you can reach al the integers on the codomain.

3 0
3 years ago
An environmental study of a certain community suggests that t years from now, the average level of carbon monoxide in the air wi
icang [17]

Answer:

3.4625

Step-by-step explanation:

Given the equation:

Q(t)=0.05t^2 + 0.1t + 3.4 parts per million

Where t = time in years

By approximately how much will the carbon monoxide lvel change during the coming 6 months?

t = 6 months = 6/12 = 0.5 year

Q(0.5) = 0.05(0.5)^2 + 0.1(0.5) + 3.4 parts per million

Q(0.5) = 0.05(0.25) + 0.05 + 3.4

Q(0.5) = 0.0125 + 0.05 + 3.4

Q = 3.4625

Carbon monoxide level will change by approximately 3.4625 parts per million in 6 months

7 0
3 years ago
B
Alenkinab [10]

Answers:  

hypotenuse = 20 feet

longer leg = 16 feet

======================================================

Explanation:

c = x = length of the hypotenuse

a = x-4 = length of one of the legs

b = 12 = length of the other leg

Use the pythagorean theorem

a^2 + b^2 = c^2

12^2 + (x-4)^2 = (x)^2

144 + x^2 - 8x + 16 = x^2

144 - 8x + 16 = 0 .... the x^2 terms cancel

160-8x = 0

160 = 8x

8x = 160

x = 160/8

x = 20 is the hypotenuse

x-4 = 20-4 = 16 is the longer leg

--------

Check:

12^2+16^2 = 144+256 = 400

20^2 = 400

Since 12^2+16^2 = 20^2 is true, this means we have a right triangle with legs of 12 and 16, while the hypotenuse is 20. The answer is confirmed.

6 0
2 years ago
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