Answer:
To derive the fourth equation of motion, first we have to consider the equation for acceleration and then to rearrange it. or v2 = u2 + 2as and this equation of motion can be used to find the final velocity or the distance travelled if the other values are given.
Explanation:
v= u + at
s =( u + v ) t /2
s = ut + at2/2
v2 = u2 + 2as
Answer:
Mass of car's engine = 342.85 kg (Approx.)
Explanation:
Given values:
Force applied by car = 1,200 N
Acceleration of car' engine = 3.5 m/s²
Find:
Mass of car's engine
Computation:
⇒ Mass = Force / Acceleration
⇒ Mass of car's engine = Force applied by car / Acceleration of car
⇒ Mass of car's engine = 1,200 / 3.5
⇒ Mass of car's engine = 342.85 kg (Approx.)
Answer:2.69 cm/s
Explanation:
We know that drag force
Fd=6 πμ r v
μ=Dynamic viscosity
r=radius
v=terminal velocity
Bouncy force
Fb= ρ V g
V=volume
At the condition of terminal velocity
when going down ( aluminum)
---------1
when going up ( air)
-----------2
m =mass of object
Divide 1 and 2
divide by 
in R.H.S
Answer:
b . Move the conductor near a magnet
