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allochka39001 [22]
3 years ago
10

How to derive the fourth equation of motion?

Physics
1 answer:
Leya [2.2K]3 years ago
6 0

Answer:

To derive the fourth equation of motion, first we have to consider the equation for acceleration and then to rearrange it. or v2 = u2 + 2as and this equation of motion can be used to find the final velocity or the distance travelled if the other values are given.

Explanation:

v= u + at

s =( u + v ) t /2

s = ut + at2/2

v2 = u2 + 2as

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Lori wants to send a box of oranges to a friend by mail. The box of oranges cannot exceed a mass of 10.222 Kg. If each orange ha
Sergeu [11.5K]

Explanation:

Given that,

The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.

The mass of each orange is 198 g

We know that,

1 kg = 1000 g

10.222 kg = 10.222×1000 g

Let there are n number of oranges. So,

n=\dfrac{10.222\times 1000\ g}{198\ g}\\\\n=51.92\approx 52\ \text{oranges}

It means she can send 52 oranges and it is maximum quantity.

4 0
4 years ago
10. The electron dot diagram for the element Ne would have ​
zmey [24]

Answer:

2,8

Explanation:

The first electron shell would have 2 electrons, the second shell would have 8 electrons. This is because Neon has a relative charge of 10.

7 0
3 years ago
Two identical balls are thrown vertically upward. The second ball is thrown with an initial speed that is twice that of the firs
9966 [12]

Answer:

The maximum height of ball 2 is 4 times that of ball 1

Explanation:

We can find the maximum height of each ball by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a=g=-9.8 m/s^2 is the acceleration of gravity (we take upward as positive direction)

s is the displacement

At the maximum height, s = h and v = 0 (the final velocity is zero), so re-arranging the equation:

h=\frac{-u^2}{2g}

The first ball is thrown with initial velocity u_1, so it reaches a maximum height of

h_1 = -\frac{u_1^2}{2g} (the quantity will be positive, since g is negative)

The second ball is thrown with initial velocity

u_2 = u_1

so it will reach a maximum height of

h_2 = - \frac{u_2^2}{2g}=-\frac{(2u_1)^2}{2g}=4(-\frac{u_1^2}{2g}) = 4h_1

So, its maximum height will be 4 times the maximum height reached by ball 1.

8 0
3 years ago
The heat that builds up in the greenhouse effect initially enters the atmosphere as
Trava [24]

Answer:

Solar radiation

Explanation:

Gases such as methane , ozone, and Carbon dioxide are known as the greenhouse gases. When the gases are heated up they usually build up in the greenhouse effect and after a while they enter the atmosphere as solar radiation.

It is important to note that the release of the gases is usually the first(initial) release of the gases into the atmosphere.

7 0
3 years ago
Read 2 more answers
How much work is done in pushing an object 7.0 m across a floor with a force of 50 N and then
attashe74 [19]

Answer:

35/2 J/s

Explanation:

Just use the 2 formulas

Work done = Force * distance moved

Power = Work done/time

WD = 7 * 50  = 350

Power = 350 / 20

= 35/2 J/s

8 0
3 years ago
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