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Levart [38]
3 years ago
11

Can you help me pls :>​

Mathematics
1 answer:
postnew [5]3 years ago
7 0

Answer:

30

Step-by-step explanation:

6x6 is 36 then -6 is 30

for b it would be a^2-6

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Ms.Franks drives a maximum of 150 miles per week to and from work. She works 5 days per week. Write an inequality that shows m t
Phoenix [80]

Answer:

Step-by-step explanation:

Let m represent the number of miles that she drives per day.

She works 5 days per week. This means that the total number of miles that she drives in a week would be

5 × m = 5m

Ms.Franks drives a maximum of 150 miles per week to and from work. Therefore, the inequality that shows m the number of miles she drives per day would be

5m ≤ 150

m ≤ 150/5

m ≤ 30

7 0
4 years ago
Plz help asap i need the right answer who ever is right get brainiest
e-lub [12.9K]

X=18

Step-by-step explanation:

5 0
3 years ago
How does the graph of g(x) = (x + 4)^3 − 6 compare to the parent function f(x) = x^3?
ANTONII [103]

Answer:

  D) g(x) is shifted 4 units to the left and 6 units down

Step-by-step explanation:

When -6 is added to the y-value, it moves the point on the graph down 6 units. Compared to f(x), g(x) is 6 units down.

Transforming the function using f(x -h) shifts its graph h units to the right. Here, we have h=-4, so the graph is shifted 4 units to the left.

5 0
3 years ago
What is the length of leg s of the triangle below?
andreev551 [17]

Answer:creo que es la E

Step-by-step explanation:

8 0
3 years ago
On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t
Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

The angle at which hailstones falling relative to the cyclist is \theta = 36.86^\circ

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of 2\hat{i}-6\hat{k}\text{ m/s} . If a cyclist travels through the hail at 10\hat{i} \text{ m/s}.

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is V_h=2\hat{i}-6\hat{k}\text{ m/s}

The velocity of the cyclist travels through the hail is V_c=10\hat{i} \text{ m/s}

The velocity of the hail relative to the cyclist is given by,

V_{hc}=V_h-V_c

Substitute the value in the formula,

V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}

V_{hc}=-8\hat{i}-6\hat{k}

So, The velocity of the hail relative to the cyclist is V_{hc}=-8\hat{i}-6\hat{k}

Now, The angle of hails falling relative to the cyclist is given by

\theta = \tan^{-1}(\frac{-6}{-8})

\theta = \tan^{-1}(\frac{3}{4})

\theta = 36.86^\circ

So, The angle at which hailstones falling relative to the cyclist is  \theta = 36.86^\circ

4 0
4 years ago
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