Answer:
Statement, Reason
Given segment RV = segment TU, Given
m∠R = m∠T, Given
Segment RS ≅ segment ST, Base angles theorem
ΔRSV ≅ ΔTSU, SAS rule of congruency
Segment SV ≅ segment SU, CPCTC
VU ≅ UV, Reflexive property
RU = RV + VU, TV = TU + UV, Addition of segments
RV + VU ≅ TU + UV, Addition property of equality
RU ≅ TV, Transitive property of addition
ΔRSU ≅ ΔTSV, SSS rule of congruency
Step-by-step explanation:
Where:
SAS- Side Angle Side
CPCTC -Congruent Parts of Congruent Triangles are Congruent
SSS -Side Side Side
Answer:
Joe: 3 hrs
Janet: 6hrs
Step-by-step explanation:
joe takes x hours
so in 1 hr he does 1/x of the garden
janet takes 2x hours
so in 1 hr she does 1/(2x) of the garden
In one hour together they do 1/2 of the garden
1/x + 1/(2x) = 1/2
2/(2x) + 1/(2x) = 1/2
3/(2x) = 1/2
Cross multiply
6 = 2x
x = 3
Joe: 3 hrs
Janet: 6hrs
B = 2A/h
The way you would get this is first by clearing the fraction. So in order to clear the fraction, you have to multiply the equation by the denominator.
2(A = 1/2bh)
2A = 1bh
2A = bh
Then you have to isolate the variable. So you'd divide bh by h in order to get b by itself. So you'd end up with:
2A/h = bh/h
2A/h = b
Answer:
ghyohgfyu
Step-by-step explanation:
Answer:
The first option 
.
Step-by-step explanation:
To have exactly 2 real and two non real solutions, the degree of the polynomial must be a degree 4. Degree is the highest exponent value in the polynomial and is also the number of solutions to the polynomial. This polynomial ha 2 real+2 non real= 4 solutions and must be 
. This eliminates the bottom two solutions.
In order to have two real and two non real solutions, the polynomial must factor. If it factors all the way like
This means x=0, 10, -10 are real solutions to the polynomial. It has no non real solutions. This eliminates this answer choice.
Only answer choice 1 meets the requirement.
