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2 years ago

10

please help now it kinda important i get it done soon or i cant go to a dance for my school tomorrow. im begging u ill give u 5

stars and a thanks and maby even a showt out thats how much this means to me.

1 answer:

harkovskaia [24]2 years ago

6 0

Answer: 352496

Step-by-step explanation:

First, to find 20% of 440,620, you can multiply:

0.2 x 440,620 = 88,124

Then, to find the new weight of the ship, you can subtract the 20% that was just found (88,124) from the ship's original weight (440,620) to get:

440,620 - 88,124 = 352,496

Therefore, the ship's weight is now 352496.

I hope this helps!

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A large cable company reports the following:

Step2247 [10]

Answer:

$P(Cable\ TV\ only) = 50\%$

$P(Internet\ |\ cable\ TV) = 31.25\%$

$P(exactly\ 2\ services) = 23\%$

$P(Internet\ and\ cable\ TV \only) = 23\%$

Step-by-step explanation:

Given

$Cable\ TV = 80\%$

$Internet = 44\%$

$Telephone = 29\%$

$Cable\ TV\ and\ Internet = 25\%$

$Cable\ TV\ and\ Telephone = 20\%$

$Internet\ and\ Telephone = 23\%$

$All\ Services = 15\%$

Solving (a): A) P(cable TV only).

First, we calculate n(cable TV only)

This is calculated as:

$n(cable\ TV\ only) = (Cable\ TV) - (Cable\ TV\ and\ Internet) - (Cable\ TV\ and\ Telephone) + (All\ Services)$

$n(cable\ TV\ only) = 80\% - 25\% - 20\% + 15\%$

$n(cable\ TV\ only) = 50\%$

The probability is:

$P(Cable\ TV\ only) = \frac{n(Cable\ TV\ only)}{100\%}$

$P(Cable\ TV\ only) = \frac{50\%}{100\%}$

$P(Cable\ TV\ only) = 50\%$

Solving (b): P(Internet | cable TV).

This is calculated as:

$P(Internet\ |\ cable\ TV) = \frac{Cable\ TV\ and\ Internet}{Cable\ TV}$

$P(Internet\ |\ cable\ TV) = \frac{25\%}{80\%}$

$P(Internet\ |\ cable\ TV) = \frac{25}{80}$

$P(Internet\ |\ cable\ TV) = 31.25\%$

Solving (c): P(exactly 2 services).

This is calculated as:

$P(exactly\ 2\ services) = (Cable\ TV\ and\ Internet - All) + (Cable\ TV\ and\ Telephone - All) + (Internet\ and\ Telephone - All)$

$P(exactly\ 2\ services) = (25\% - 15\%) + (20\% - 15\%) + (23\%-15\%)$

$P(exactly\ 2\ services) = (10\%) + (5\%) + (8\%)$

$P(exactly\ 2\ services) = 23\%$

Solving (d): P(Internet and cable TV only).

This is calculated as:

$P(Internet\ and\ cable\ TV \only) = \frac{(Internet\ and\ cable\ TV \only)}{100\%}$

$P(Internet\ and\ cable\ TV \only) = \frac{23\%}{100\%}$

$P(Internet\ and\ cable\ TV \only) = \frac{23\%}{1}$

$P(Internet\ and\ cable\ TV \only) = 23\%$

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