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Arturiano [62]
2 years ago
13

Toluene (C7H8) burns in oxygen to produce cardon dioxide and water. (a) How many grams of oxygen are neccessary for the combusti

on of 94.5 g of toluene?
Chemistry
1 answer:
shepuryov [24]2 years ago
5 0
The value is 0.7 I think no jsp
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Answer:

m_{O_2}=87.2gO_2

Explanation:

Hello.

In this case, given the chemical reaction, we can compute the grams of oxygen by using the 98.2 g of water via the 2:1 mole ratio between them, the molar mass of water that is 18.02 g/mol, the molar mass of gaseous oxygen that is 32.00 g/mol and the following stoichiometric procedure relating the given information:

m_{O_2}=98.2gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molO_2}{2molH_2O}*\frac{32.00gO_2}{1molO_2}   \\\\m_{O_2}=87.2gO_2

In which the result is displayed with three significant figures because the given mass of water 98.2 g, has three significant figures too.

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