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n200080 [17]
3 years ago
10

140 is what percent less than 160?

Mathematics
2 answers:
VMariaS [17]3 years ago
7 0

Answer:

12.5!!

Step-by-step explanation:

irinina [24]3 years ago
7 0

Answer:

It is 12.5% lesser

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Dafna1 [17]
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4 years ago
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Find the product of the solutions
irina1246 [14]

Answer:

A.  -41/15.

Step-by-step explanation:

15x^2 + 23x - 41 = 0

Product of the roots of ax^2 + bx + c = c/a.

Thus the product of the roots of this equation = -41/15.

7 0
3 years ago
Find the quadratic function f (x )equals ax squared plus bx plus c for which f (1 )equals negative 2​, f (negative 3 )equals 26​
BaLLatris [955]

Answer:

f(x) =4x² + x - 7

Step-by-step explanation:

f(x) = ax² + bx + c

f(1) = a + b + c

f(-3) = 9a - 3b + c

f(3) = 9a + 3b + c

a + b + c = -2 -----(1)

c = -2-a-b -----(2)

9a - 3b + c = 26 ------(3)

9a + 3b + c = 32 -------(4)

(2)->(3)

9a-3b-2-a-b = 26

8a-4b = 28

4(2a-b) = 28

2a-b = 7 ----(5)

(2)->(4)

9a+3b-2-a-b = 32

8a+2b = 34

2(4a+b) = 34

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(5)+(6)

6a = 24

a = 4

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b = 1

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c = -2-4-1

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5 0
3 years ago
Use f’( x ) = lim With h ---&gt; 0 [f( x + h ) - f ( x )]/h to find the derivative at x for the given function. 5-x²
beks73 [17]
<h2>Answer:</h2>

The derivative of the function f(x) is:

                 f'(x)=-2x

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as:

f(x)=5-x^2

We have:

f(x+h)=5-(x+h)^2\\\\i.e.\\\\f(x+h)=5-(x^2+h^2+2xh)

( Since,

(a+b)^2=a^2+b^2+2ab )

Hence, we get:

f(x+h)=5-x^2-h^2-2xh

Also, by using the definition of f'(x) i.e.

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f'(x)= \lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-(5-x^2)}{h}\\\\\\f'(x)=\lim_{h \to 0} \dfrac{5-x^2-h^2-2xh-5+x^2}{h}\\\\i.e.\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2-2xh}{h}\\\\f'(x)=\lim_{h \to 0} \dfrac{-h^2}{h}+\dfrac{-2xh}{h}\\\\f'(x)=\lim_{h \to 0} -h-2x\\\\i.e.\ on\ putting\ the\ limit\ we\ obtain:\\\\f'(x)=-2x

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          f'(x)=-2x

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3 years ago
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