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Ahat [919]
3 years ago
8

Identify each of the following mixtures as either homogeneous or heterogeneous and as a solution, a suspension, or a colloid.

Chemistry
2 answers:
stiv31 [10]3 years ago
8 0

both are heterogenous and suspension. Yes they are the same.

Sergeeva-Olga [200]3 years ago
4 0

Blood.

<span>Blood is heterogeneous because it has corpuscles (blood cells and platelets) physically suspended in blood plasma.   Blood plasma and the corpuscles have different properties and can be separated by methods such as centrifugation. Also, blood is considered a colloid suspension because it has the properties of both a colloid and a suspension. This is because the blood plasma acts as a colloid. More so, if blood was left to settle,then the blood cells would collect at the bottom hence taking the characteristic of a suspension. </span>

<span>Salad dressing.</span>

<span>Depending on the type of salad, it can either be a heterogeneous or homogeneous mixture. If the salad dressing is only of vinegar or any other oil, then it is a homogenous mixture. However, if it involves a mixture of vinegar and other oils, pepper, herbs, and etcetera, then it is a heterogeneous mixture</span>




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Radon is produced by uranium rocks underneath a house.
6 0
4 years ago
Define<br>Equivalent weight of a<br>Chemical substance​
SSSSS [86.1K]
Equivalent weight, in chemistry, the quantity of a substance that exactly reacts with, or is equal to the combining value of, an arbitrarily fixed quantity of another substance in a particular reaction. ... The equivalent weight of an element is its gram atomic weight divided by its valence (combining power).


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4 0
3 years ago
Write the name of the alkyne next to the drawing of the molecule. (2 points)
azamat

1) 1-Pentyne

2) But-2-yne

3) Ethyne

4) 1-Propyne

5) 1-Butyne

6) Pent-2-yne

<h3>What is alkyne?</h3>

Molecules that contain a triple bond between two carbon atoms are known as alkynes.

1) The number of carbon on the longest chain = 5, (two carbon atoms between the triple bond) therefore the prefix is pen-

The functional group is the triple bond on the first carbon with the suffix -yne

The name of the compound is 1-Pentyne

2) There are 4 carbon atoms on the longest chain, therefore, the prefix is but-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom

Therefore, the name of the compound is But-2-yne

3) The triple bond functional group is between the only two carbon atoms, therefore, the name is Ethyne

4) The number of carbon atoms = 3, with a prefix prop-, and the functional group on the first carbon atom on the longest chain is the triple bond, with suffix -yne

Therefore, the name of the compound is 1-Propyne

5) The number of carbon atoms on the longest chain = 4, the prefix is but-

The location of the triple bond functional group (suffix -yne) is on the first carbon atom

Therefore, the name is 1-Butyne

6) The number of carbon atoms on the longest chain = 5, the prefix of the compound is pen-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom, therefore;

The name of the compound is Pent-2-yne

Learn more about alkyne here:

brainly.com/question/23508203

#SPJ1

6 0
2 years ago
Each 5-ml teaspoon of Extra Strength Maalox Plus contains 450 mg of magnesium hydroxide and 500 mg of aluminum hydroxide. How ma
Art [367]

Answer:

0.0347 moles of hydronium ions

Explanation:

The equation of the neutralization reaction between hydroxide and hydronium ions is given below:

H₃O+ (aq) + OH- (aq) ----> 2 H₂O (l)

From the equation above, 1 mole of hydroxide ions will neutralize one mole hydronium ions.

The moles of hydroxide ions present in 1 teaspoon or 5 mL of antacid product is calculated as follows:

Number of moles = mass / molar mass

Molar mass of Magnesium hydroxide, Mg(OH)₂ = 58 g/mol

Molar mass of aluminium hydroxide, Al(OH)₃ = 78 g/mol

Mass of magnesium hydroxide = 450 g = 0.45 g

Mass of aluminium hydroxide = 500 mg = 0.5 g

Moles of magnesium hydroxide = (0.45/58) moles

Moles of aluminium hydroxide = (0.5/78) moles

Equation of the ionization of magnesium hydroxide and aluminium hydroxide is given below:

Mg(OH)₂ (aq) ----> Mg²+ (aq) + 2 OH- (aq)

Al(OH)₃ (aq) ---> Al³+ (aq) + 3 OH- (aq)

Number of moles of hydroxide ions present in (0.45/58) moles of magnesium hydroxide = 2 × (0.45/58) moles = 0.0155 moles

Number of moles of hydroxide ions present in (0.5/78) moles of aluminium hydroxide = 3 × (0.5/78) moles = 0.0192 moles

Total moles of hydroxide ions = 0.0155 + 0.0192 = 0.0347 moles hydroxide ions

Therefore, 0.0347 moles of hydroxide ions will neutralize 0.0347 moles of hydronium ions.

3 0
3 years ago
How many grams of nh3 can be produced from 3.72 mol of n2 and excess h2.
olganol [36]
N₂       + 3H₂ ⇒ 2NH₃
1mol       :         2mol
3,72mol  :         7,44mol

n = 7,44mol
M = 17g/mol

m = n * M = 7,44mol * 17g/mol = 126,48g
7 0
3 years ago
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