What is the marginal cost of increasing production from 5,000 units to 6,000 units?

narvez 5. Everyone in Dobby's family has a long nose and they brag that they are from a purebred line. Viola has a stubby nose.

mote1985 [20]

Assuming a single diallelic gene coding for the trait and expressing complete dominance, the phenotypes, genotypes, and probabilities of getting each of them vary according to the parentals' genotypes. See the options below.

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Since I do not have the genotypes from #2, I will provide different potential scenarios for this question.

I advise you to check on them and see which one matches the genotype from #2.

Let us assume a single diallelic gene is coding for the trait and expresses complete dominance.

<h3 /><h3>SCENARIO 1 ⇒ long nose is the dominant trait</h3>

Let us say that

L is the dominant allele and codes for long nose

l is the recessive allele and codes for stubby nose

Since long nose is dominant over stubby nose

LL and Ll ⇒ long nose

ll ⇒ stubby nose

If Dobby comes from a purebred family and has long nose, his genotype must be LL.

And if Viola has stubbi nose, her genotype must be ll.

Cross 1

Parentals) LL x ll

Gametes) L L l l

Punnett square) L L

l Ll Ll

F1) Genotype ⇒ 100% heter0zyg0us Ll

Phenotype ⇒ 100% long-nosed

There is 100% chances for a child to have a long nose

There is 0% chances for a child to have a stubby nose

These children are not purebred

**********

<h3>SCENARIO 2 ⇒ Stubby nose is the dominant trait</h3>

Let us say that

S is the dominant allele and codes for stubby nose

s is the recessive allele and codes for long nose

Since stubby nose is dominant over long nose

SS and Ss ⇒ stubby nose

ss ⇒ long nose

If Dobby comes from a purebred family and has long nose, his genotype must be ss.

And if Viola has stubbi nose, her genotype must be either SS or Ss.

There are two possible crosses.

Cross 1 : Violet is h0m0zyg0us dominant SS

Parentals) SS x ss

Gametes) S S s s

Punnett square) S S

s Ss Ss

F1) Genotype ⇒ 100% heter0zyg0us Ss

Phenotype ⇒ 100% stubby-nosed

There is 100% chances for a child to have a stubby nose

There is 0% chances for a child to have a long nose

These children are not purebred

Cross 2: Violet is heter0zyg0us, Ss

Parentals) Ss x ss

Gametes) S s s s

Punnett square) S s

s Ss ss

F1) Genotype ⇒ 50% heter0zyg0us Ss and 50% h0m0zyg0us recessive ss

Phenotype ⇒ 50% stubby-nosed and 50% long-nosed

There is 50% chances for a child to have a stubby nose

There is 50% chances for a child to have a long nose

These children are not purebred

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You can learn more about single gene crosses at

brainly.com/question/12653314?referrer=searchResults

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