We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
Answer:
That's basically how you solve it
Answer:
48.96
Step-by-step explanation:
Perform the two multiplications from left to right:
2.23x3.42x6.42 becomes:
7.6266 · 6.42, or
48.96
Answer:
I guess this is how to do it....
3×(1/3 of x + 8)=11.
use the 3 to multiply the numbers in the bracket.
3x+24=11.
3x=11-24.
3x=-13.
x= -13/3.
x= -4.33.
Answer:
its b. cuz got the friggen question wrong when i did it. >:(