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White raven [17]
2 years ago
5

In the bohr model of the hydrogen atom, the energy required to excite an electron from n = 2 to n = 3 is _______________ the ene

rgy required to excite an electron from n = 3 to n = 4?
Chemistry
1 answer:
12345 [234]2 years ago
6 0

In the bohr model of the hydrogen atom, the energy required to excite an electron from n = 2 to n = 3 is <u>greater than</u> the energy required to excite an electron from n = 3 to n = 4

Bohr's energy levels:

The essential concept of Bohr's atomic model is that electrons occupy specified orbitals that call for the electron to have a certain amount of energy. An electron needs to be in one of the permitted orbitals and have the correct amount of energy needed for that orbit in order to be in the electron cloud of an atom. An electron would require less energy to orbit near the nucleus, while an electron would need more energy to orbit away from the nucleus. Energy levels are the potential orbits. One of Bohr's models' flaws was that he was unable to explain why just specific energy levels or orbits were permitted.

It is evident that the energy required to escape an electron from n=2 to n=3 is greater than the energy required to exit an electron from n=3 to n=4. This is because as n increases, the energy levels move closer to one another.

Learn more about Bohr's model here:

brainly.com/question/3964366

#SPJ4

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(( PLEASE HELP QUICK ))Which expression can be used to calculate the ratio of the rate of effusion of gas A to the rate of effus
borishaifa [10]

Answer:

The square root of the molar mass of B ÷ the square root of the molar mass of A  

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r \propto \dfrac{1}{\sqrt{M}}

If you have two gases A and B, the ratio of their rates of effusion is

\dfrac{r_{\text{A}}}{r_{\text{B}}} = \sqrt{\dfrac{M_{\text{B}}}{M_{\text{A}}}}

3 0
3 years ago
A 280 mL bubble contains 0.283 g of a gas at 0.951 atm and 25.0°C What is the molar mass of this gas?
tekilochka [14]

Answer: 28.3 g/mol

Explanation:

According to the ideal gas equation:'

PV=nRT

P= Pressure of the gas = 0.951 atm

V= Volume of the gas = 280 mL = 0.28 L     (1L=1000 ml)

T= Temperature of the gas = 25°C=(25+273)K=298 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm/K mol

n=\frac{PV}{RT}=\frac{0.951\times 0.28L}{0.0821 \times 298}=0.010moles

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

0.010=\frac{0.283}{\text {Molar mass}}

{\text {Molar mass}}=28.3g/mol

Thus the molar mass of the gas is 28.3 g/mol.

7 0
3 years ago
The sum of all percent abundances for magnesium is equal to 100. explain why this is reasonable.
kow [346]
Elements occur naturally in different forms called isotopes. These are the same atoms with the same number of protons but has different number of neutrons. Almost all elements exist in nature as such. The amounts of these isotopes are expressed in terms of percent abundances and since it is in a percentage units, the sum of all the abundances should equate to 100 percent or else the calculation is wrong. This is not true onlt for magnesiun but with all of the elements. The atomic mass of these elements also depends on the percent abundances of the isotopes since it is a weighted average value of the individual masses of the isotopes.
7 0
3 years ago
Read 2 more answers
How many grams of hydrogen reacts with 32 g of oxygen to produce 34 g of hydrogen peroxide
nordsb [41]

Answer:

2 grams.

Explanation:

H2 + O2 --->  H2O2

Using molar masses:

2*1 g hydrogen   reacts with 2*16  g oxygen.

so 2g H2 reacts with 32 g O2.

8 0
3 years ago
Identify each of these substances as acidic, basic, or neutral.
DochEvi [55]

Answer:

<u>Rain Water:</u> Acidic

<u>Cola:</u> Acidic

<u>Tomato Juice:</u> Acidic

<u>Liquid Drain Cleaner:</u> Basic

6 0
4 years ago
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