The molarity of a saline solution that contain 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml solution is 0.15 M
<u><em>calculation</em></u>
Molarity = moles /volume in liters
volume in liters = 100.0 ml / 1000 = 0.1 L
moles = mass÷ molar mass
= 0.900 g ÷58.44 g/mol =0.015 moles
molarity is therefore = 0.015 moles / 0.1 L =0.15 M
In setting up your equipment in front of the fume hood to eliminate
any vapors during the experiment. Use an iron ring stand with iron ring to back
up the clay triangle to clasp the crucible and lid. Alter the height of the
iron ring so the end of the crucible is about one centimeter above the inner
blue cone of the strong flame.
2 KMnO4 (aq) + 5 H2O2 (aq) + 3 H2SO4 (aq) → 5 O2 (g) + 2 MnSO4 (aq) + K2SO4 (aq) + 8 H2O (l)