Answer:
(a).
![order \: of \: A = 2 \\ order \: of \:B = 0 \\ rate = k[A] {}^{2} [B]](https://tex.z-dn.net/?f=order%20%5C%3A%20of%20%5C%3A%20A%20%3D%202%20%5C%5C%20order%20%5C%3A%20of%20%5C%3AB%20%20%3D%200%20%5C%5C%20rate%20%3D%20k%5BA%5D%20%7B%7D%5E%7B2%7D%20%5BB%5D)
(b)
(c). The rate increases because kinetic energy of reactant molecules increases.
Answer:
Depletion is the movement of the cost of natural resources from a company's balance sheet to its income statements. The objective is to match on the income statement the cost of the natural resources that were sold with the revenues of the natural resources that were sold.
Explanation:
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Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is LiOH.
We are given:
Putting values in above equation, we get:
Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
Is this a multiple choice?
Answer:
21.5mL of a 0.100M HCl are required
Explanation:
The sodium phenoxide reacts with HCl to produce phenol and NaCl in a 1:1 reaction.
To solve this question we need to find the moles of sodium phenoxide. These moles = Moles of HCl required to reach equivalence point and, with the concentration, we can find the needed volume as follows:
<em>Mass NaC6H5O:</em>
1.000g * 25% = 0.250g NaC6H5O
<em>Moles NaC6H5O -116.09g/mol-</em>
0.250g NaC6H5O * (1mol/116.09g) = 2.154x10⁻³ moles = Moles of HCl required
<em>Volume 0.100M HCl:</em>
2.154x10⁻³ moles HCl * (1L/0.100mol) = 0.0215L =
<h3>21.5mL of a 0.100M HCl are required</h3>
