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2 years ago

At the Olympics, Michael

Mathematics

1 answer:

UkoKoshka [18]2 years ago

8 0

Answer:

900 meters

Step-by-step explanation:

There are about 3 feet in a meter, so to find the answer you have to add up all the meters he swam and then multiply it by that.

So the equations will be: 100+200=300, 300x3=900.

Hope you get an A! <3

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A shop sells chocolate, vanilla and strawberry ice creams. 45% of the ice creams sold are vanilla, and 1/4 are strawberry. What

OverLord2011 [107]

Answer:

30%

Step-by-step explanation:

Well since we know that 45% is vanilla that means we have part of our answer

Also we know we sold 1/4 strawberry which in percent that would be 25%

If we add 45% with 25% 45+25=70 then since something can only be 100%

100%-70%=30%

you sold 30% chocolate

<3 <;

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3 years ago

Which of the following best describes the solution to the system of equations below?

8090 [49]

The answer is D !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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3 years ago

Which graph represents the function f(x) = 1/x - 1?

HACTEHA [7]

Answer:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

f(x) = 1/x - 1

Domain

All real numbers except for {0}

4 0

3 years ago

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A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set

lara [203]

A circle with center $(3,0)$ and radius $5$ has equation

$(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x = 16$

If we substitute $y=2x+k$ in this equation, we have

$x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0$

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

$\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0$

The expression simplifies to

$-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89$

The solutions to the associated equation are

$k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}$

So, the parabola is negative between the two solutions:

$-6-5\sqrt{5}$

8 0

3 years ago

What are the solutions to the quadratic equation below in factored form?

saw5 [17]

Answer:

$\cfrac{-4}{3}$ and $\cfrac{1}{2}$ .

Step-by-step explanation:

Equation:

$\rm \: \: (2x - 1)(3x + 4) = 0$

Solution:

Set factors equal to zero,that is:

$(2x - 1) = 0 \: \: \: \: \: \: \: \: \: \: \: ...(1)$

$(3x + 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \: ...(2)$

Solving for equation 1:

$2x - 1 = 0$
$2x = 0 + 1$
$2x = 1$

$\boxed{x = \cfrac{ 1}{2} }$

Solving for equation 2:

$3x + 4 = 0$
$3x = 0 - 4$
$3x = - 4$

$\boxed{x = \cfrac{ - 4}{3} }$

Hence,the solutions to the quadratic equation in factored form is $\cfrac{-4}{3}$ and $\cfrac{1}{2}$ .

$\rule{225pt}{2pt}$

Good luck on your assignment!

4 0

2 years ago

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