For
y=a(x-h)^2+k
vertex is (h,k)
given
y=1(x-2)^2-5
the vertex is (2,-5)
tha'ts quadrant 4
andswer is 2nd one
Answer:
4
Step-by-step explanation:
multiply 10 by w and 3
equation becomes 10w+30=70
subtract 30 by both sides
equation becomes 10w=40
divide both sides by 10
equation becomes w=4
your answer is 4!
Answer:
(6,1)
Step-by-step explanation:
1.) group the x and y terms (and move the constant to the other side)
x²-12x+y²-2y= -12
divide the coeficcents for the terms with just 1 or 1 x variable by 2 and then square it (and add that to both sides)
x²-12x+36+y²-2y+1= -12+36+1
factor
(x-6)²+(y-1)²= 25
the center is therefore (6,1)
Answer:
Step-by-step explanation: -9<em>X3</em>+12x2-x-2
Answer:
5y-4x= -7 :
Slope = 
= 0.800
<em>x </em>- <em>intercept = </em>
= 1.75000
<em>y - intercept = - </em>
= -1.40000 <------both of these numbers a negative
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2y+4y = 14 :
<em>y = </em>
= 2.333
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<em>Hope this helped & good luck <333</em>
