Answer:
Proton, neutron, electron
Explanation:
The atom consists of a nucleus, where almost all the mass is concentrated, and electrons orbiting around the nucleus.
The nucleus consists of two types of particles:
- Proton: it has a mass of 
, and a positive electric charge of +e (
)
- Neutron: it has a mass of 
, and it has no electric charge
The third particle that makes an atom is the electron, that orbit around the nucleus:
- Electron: it has a mass of 
, and it has a negative electric charge of -e (
)
Using the law of conservation of momentum
m1u1+m2u2=m1v1+m2v2
Where m1 is mass of first object
m2 is mass of second object
u1 and u2 are initial velocities of object 1 and 2 respectively
v1 and v2 are final velocities of object 1 and 2 respectively
Here, they are moving as a system after collision. Thus they will posses same final velocity
m1u1 +m2u2=v(m1+m2)
Substituting values
600*4+0=v(600+400)
2400=v*1000
v=2.4 m/s
Now momentum of system
p=Mv
p=(600+400)*2.4
p=1000*2.4
Therefore p=2400 kg m/s
Hope this helps :)
The Electric field is zero at a distance 2.492 cm from the origin.
Let A be point where the charge 
C is placed which is the origin.
Let B be the point where the charge 
C is placed. Given that B is at a distance 1 cm from the origin.
Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.
i.e., at distance 'x' from B.
Using Coulomb's law, 
,
= 
k is the Coulomb's law constant.
On substituting the values into the above equation, we get,
Taking square roots on both sides and simplifying and solving for x, we get,
1.67x = 1+x
Therefore, x = 1.492 cm
Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.
Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926
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<span>radiation, hydrogen, and helium </span>
Weight equals mass times gravitational acceleration=400N, so mass=400/9.8=41kg approx.
