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ziro4ka [17]
4 years ago
9

A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step

s on the brake pedal and manage to stop the car in 6 s. The distance of the cows from the car when the driver spotted them is 160 m. How far are the cows from the car when the car stops?
Physics
1 answer:
Crazy boy [7]4 years ago
6 0
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
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Answer

Work done will be 14.7\times 10^{-6}J and it will be positive

Explanation:

We have given charge 2.1\times 10^{-6}C

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Let V_1=15V\ and\ V_2=8volt

So potential difference V=V_1-V_2=15-8=7volt

We know that work done W=QV, here Q is charge and V is potential difference

So work done W=QV=2.1\times 10^{-6}\times 7=14.7\times 10^{-6}J

It will be positive work done because work is done in moving charge from higher potential to lower potential  

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4 years ago
What is the relationship between force and momentum?
KatRina [158]

Answer:

Explanation:

B

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3 years ago
Consider a standing wave in a one dimensional ideal medium of length "D" (like a vibrating string).
stira [4]

Answer:

a) 20 nodes    b) zero nodes

Explanation:

When we have standing waves in a bend we have nodes at the ends and the equation describes the number of possible waves in the string is

         L = n λ/2

Where λ is the wavelength, L is the length of the string, in our case it would be D and n is an entered. We can strip the wavelength of this expression

       

       λ = 2L / n

Let's calculate what value of n we have for a wavelength equal to D/10

       λ = 2D / n

       λ = D / 10

We match and calculate

       2D / n = D / 10

       2 / n = 1/10

       n = 20

Perform them for  λ = D / 20

       λ = 2D / n

       2D / n = D / 20

       n = 2 20 = 40

Since n is an inter there should be a wavelength for each value of n in the bone period there should be 20 different wavelengths

B) for La = 10D

       2D / n = 10D

       1 / n = 5

       n = 1/5 = 0.2

 

La = 20D

       2D / n = 20D

       1 / n = 10

      n = 1/10 = 0.1

These numbers are not entered so there can be no wave in this period

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3 years ago
A copper wire has a diameter of 4.00 x 10-2 inches and is originally 10.0 ft long. What is the greatest load that can be support
jek_recluse [69]

Complete question is;

A copper wire has a diameter of 4.00 × 10^(-2) inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit? Use the value of 2.30 × 10⁴ lb/in² for the elastic limit of copper.

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Thus;

Elastic limit = Max stress

Formula for max stress is;

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Thus;

Elastic limit = F_max/A

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Plugging in the relevant values into the elastic limit equation, we have;

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F_max = 2.30 × 10⁴ × (π × 0.02²)

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Answer:

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