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alex41 [277]
2 years ago
6

Please answer correctly!! You will be reported if you don't!!

Mathematics
2 answers:
algol [13]2 years ago
7 0
We need the question lol i don’t think u uploaded it
serious [3.7K]2 years ago
5 0

Answer:

QUESTION?

Step-by-step explanation:

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I just need examples of these things, I have to make my own problems and solve them:
poizon [28]
1) x+17=20
x-10=30

2) x/4=20
x/30=2

3) 4(x+5)=40

4) x+3.2=6

5) A pizza place sells pizza for $5 per box. If I had $20 how many pizzas can I buy in all? (5x=20)

Hope this helps! Have a wonderful day.
6 0
3 years ago
Every Sunday, Tamika sells pieces of homemade fudge at a local carnival. Each piece of fudge weighs 34 pound. Next Sunday, Tamik
Aloiza [94]

Answer:

hshshshshshshshsiqkZjfdudiodjfhfbbxdudijdd

5 0
3 years ago
Find the slope on the line
katovenus [111]

Answer:

top left corner

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
106. Find the inverse g for each function f.<br> c.f(x) =23x+ 1
Arada [10]
I switched the x and y so it’s easier to see. The answer is (x-1)/(23).

7 0
3 years ago
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