Two similar triangles are shown.
2 answers:
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Basically
just put the coeficinets of each variable in the apropriate row
example
ax+by=c and
dx+ey=f
would go in like this
![\left[\begin{array}{ccc}a&b&|c\\d&e&|f\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%26%7Cc%5C%5Cd%26e%26%7Cf%5Cend%7Barray%7D%5Cright%5D%20)
so
3x+1=1 and
0x-1y=5
![\left[\begin{array}{ccc}3&1&|1\\0&-1&|5\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%26%7C1%5C%5C0%26-1%26%7C5%5Cend%7Barray%7D%5Cright%5D%20)
D is answer
just put the coeficinets of each variable in the apropriate row
example
ax+by=c and
dx+ey=f
would go in like this
so
3x+1=1 and
0x-1y=5
D is answer
Answer:
Null hypothesis:
Alternative hypothesis:
The alternative hypothesis for this case is that at least one mean is different from the others.
And the best method for this case is an ANOVA test.
Step-by-step explanation:
For this case we wnat to test if all the mean length of all face-to-face meetings and the mean length of all Zoom meetings are the same. So then the system of hypothesis are:
Null hypothesis:
Alternative hypothesis:
The alternative hypothesis for this case is that at least one mean is different from the others.
And the best method for this case is an ANOVA test.