Answer:
16 students can sit around a cluster of 7 square table.
Step-by-step explanation:
Consider the provided information.
We need to find how many students can sit around a cluster of 7 square table.
The tables in a classroom have square tops.
Four students can comfortably sit at each table with ample working space.
If we put the tables together in cluster it will look as shown in figure.
From the pattern we can observe that:
Number of square table in each cluster Total number of students
1 4
2 6
3 8
4 10
5 12
6 14
7 16
Hence, 16 students can sit around a cluster of 7 square table.
X would equal -3. 5x-3 would equal -15, and 2 negatives would equal a positive. So, -15+3 would equal -12.
Is this a true of false question if so yes
Answer:
4,5,27
Problem:
Boris chose three different numbers.
The sum of the three numbers is 36.
One of the numbers is a perfect cube.
The other two numbers are factors of 20.
Step-by-step explanation:
Let's pretend those numbers are:
.
We are given the sum is 36:
.
One of our numbers is a perfect cube.
where
is an integer.
The other two numbers are factors of 20.
and
where
.

From here I would just try to find numbers that satisfy the conditions using trial and error.






So I have found a triple that works:

The numbers in ascending order is:
