Answer:
A really out of focus picture, but I think this might be what you want.
Step-by-step explanation:
Step-by-step explanation:
please re ask question. its unvalid and please simplfy it
Answer:
The margin of error for the 90% confidence interval is of 0.038.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is:

To this end we have obtained a random sample of 400 fruit flies. We find that 280 of the flies in the sample possess the gene.
This means that 
90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Give the margin of error for the 90% confidence interval.



The margin of error for the 90% confidence interval is of 0.038.
it would be 1.496 milligrams. i hope this helps and i used a calculator
T / 3/4 ; t = 9 3/4
9 3/4 / 3/4
9 3/4 = 39/4
39/4 / 3/4
39/4 x 4/3
39 x 4 = 156
4 x 3 = 12
156/12 / 4/4 = 39/3 = 13