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Mamont248 [21]
2 years ago
10

Chelsea is having a game night at her house this Friday. She has a budget of $26. She buys two pizzas for $18 and spends the rem

aining money on soda. Each soda costs $2. How many sodas can she buy?
Mathematics
1 answer:
Alinara [238K]2 years ago
7 0

Answer:

4

Step-by-step explanation:

you'd do 26-18 which will give the leftover money after paying for the two pizzas which equal 8

each soda costs 2 dollars so you would do 8 divided by 2 which is 4

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Studentka2010 [4]

Answer:

55°

Step-by-step explanation:

m\angle C =  \frac{1}{2} (184 \degree - 74 \degree) \\  \\  \implies \: m\angle C =  \frac{1}{2} (110 \degree) \\  \\  \implies \: m\angle C =  55 \degree

8 0
3 years ago
X + y=-3 can someone help me sketching the graph of each line infinite pre-algebra
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Plot these points and then draw the line
X = 0
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X = -1
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2 years ago
A total of 56 student signed up to play in a flag football league.If each team has 10 student , how many more students will need
Ostrovityanka [42]
4.
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3 0
3 years ago
Read 2 more answers
Jahari is making hamburgers for eight party guests. When Jahari weighs all of the hamburger meat, it weighs 5 pounds 8 ounces. J
USPshnik [31]

Answer:

11 oz

Step-by-step explanation:

11 ounces for each hamburger patty

explanation:

1 pound(lbs) = 16 ounces(oz)

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/8 = Divide by 8 people

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6 0
3 years ago
An auctioneer sold a herd of cattle whose minimum weight was 920 ​pounds, median was 1160 ​pounds, standard deviation 76​, and I
katen-ka-za [31]

Answer:

minimum = $445

median = $565

standard deviation = $38

IQR = $48

Step-by-step explanation:

The minimum and the median are measures of location and are affected during addition (or subtraction) and multiplication (or division).

Satandard deviation and IQR (inter-quartile range), which are measures of dispersion, are affected by only multiplication (or division).

For the weight,

<em>minimum </em>= 920 pounds

<em>median </em>= 1160 pounds

<em>standard deviation</em> = 76 pounds

<em>IQR </em>= 96 pounds

For the price,

<em>minimum </em>= 0.50(920) - 15 = $445

<em>median </em>= 0.50(1160) - 15 = $565

<em>standard deviation</em> = 0.50(76) = $38............(<em>Subtraction discarded</em>)

<em>IQR </em>= 0.50(96) = $48........................................(<em>Subtraction discarded</em>)

7 0
3 years ago
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