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2 years ago

Temperature is a way to measure the what energy of particles of matter

Chemistry

1 answer:

Ivenika [448]2 years ago

5 0

Answer:

Temperature and Heat Temperature is the measure of the thermal energy of a substance. The hotter an object, the greater the motion of its particles, and the greater the thermal energy. Heat is the transfer or exchange of thermal energy caused by a temperature difference.

Explanation:

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If a 58 g sample of metal at 100 c is placed into calorimeter containing 60g of water at 18 c , the temperature of the water inc

tatiyna

Answer:

The water will absorb 1004.16 Joule of heat

Explanation:

Step 1: Data given

Mass of the metal = 58.00 grams

Temperature of the metal = 100.00 °C

Mass of water = 60.00 grams

Temperature of water = 18.00 °C

Final temperature = 22.00 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the amount of heat absorbed by the water in joules

Q = mass *specific heat *ΔT

⇒ with Q = the heat absorbed by water

⇒ with mass of water = 60.00 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C

Q = 60.00 * 4.184 J/g°C * 4.0 °C

Q = 1004.16 J

The water will absorb 1004.16 Joule of heat

6 0

3 years ago

Determine the number of grams of C4H10 that are required to completely react to produce 8.70 mol of CO2 according to the followi

Nitella [24]

Answer:

126.4 g of $C_{4}H_{10}$ are required

Explanation:

Balanced reaction: $2C_{4}H_{10}+13O_{2}\rightarrow 8CO_{2}+10H_{2}O$

According to balanced reaction-

8 moles of $CO_{2}$ are produced from 2 moles of $C_{4}H_{10}$

So, 8.70 moles of $CO_{2}$ are produced from $(\frac{2}{8}\times 8.70)$ moles of $C_{4}H_{10}$ or 2.175 moles of $C_{4}H_{10}$

Molar mass of $C_{4}H_{10}$ = 58.12 g/mol

So, mass of $C_{4}H_{10}$ required = $(2.175\times 58.12)g$ = 126.4 g

Hence 126.4 g of $C_{4}H_{10}$ are required

5 0

3 years ago

Calculate the volume in milliliters of a iron(II) bromide solution that contains of iron(II) bromide . Round your answer to sign

miv72 [106K]

This is an incomplete question, here is a complete question.

Calculate the volume in milliliters of a 1.29 mol/L iron(II) bromide solution that contains 275 mmol of iron(II) bromide . Round your answer to significant 3 digits.

Answer : The volume of iron(II) bromide solution is, $2.13\times 10^2mL$