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2 years ago

0.18 ( ) 0.26 which is greater

Mathematics

2 answers:

Naddik [55]2 years ago

7 0

0.26>0.18
0.26 is greater

Naddika [18.5K]2 years ago

3 0

Answer: 0.26

Step-by-step explanation: 0.26 because it has a greater value, nothing much to solve unless im missing something.

if I am missing something please comment on my answer so I can help you further with your question.

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The product of two numbers is 30. If one of the numbers is 15/, what is the other number?

PSYCHO15rus [73]

Answer:

The other number is 2 if the given number is 15.

Step-by-step explanation:

One of the numbers is 15, correct?

Let the other number be x.

15 × x = 30

x = 30/15

x = 2.

Let's check:

15 × 2 = 30.

30 = 30.

Correct!

3 0

3 years ago

Read 2 more answers

0.04 with 4 repeating as a fraction. Not the 04 repeating just the 4 is repeating. What is the answer???

Dmitriy789 [7]

Answer:

2/45

Step-by-step explanation:

0.04... is the same as 0.1 * 0.4... because we are moving it up a decimal place, it's the same as multiplying by ten: we needed to multiply by a tenth to cancel that out. 0.4... is the same as 4/9 and 0.1 is the same as 1/10. We can rewrite the expression above as: $(\frac{1}{10} )(\frac{4}{9} )$ . Multiplying the two fractions results in 4/90 which can be simplified to 2/45.

7 0

3 years ago

Could someone help me, please?

k0ka [10]

We can rewrite the expression under the radical as

$\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4$

then taking the fourth root, we get

$\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|$

Why the absolute value? It's for the same reason that

$\sqrt{x^2}=|x|$

since both $(-x)^2$ and $x^2$ return the same number $x^2$ , and $|x|$ captures both possibilities. From here, we have

The absolute values disappear on all but the $b$ term because all of $\dfrac32$ , $a^2$ and $c^4$ are positive, while $b^3$ could potentially be negative. So we end up with