Answer:
F(a,b,c,d)=b'c' + a'cd' + ab'd'.
Explanation:
The image of the corresponding k-map is attached to this answer please refer it.By the sop given in the question the k-map is formed.There are 3 groups formed 1 group of four 1's and 2 groups of 2 1's.Hence there are three sop and the sop is reduced from the previous SOP.
Answer:
FF-FF-FF-FF-FF-FF and 255.255.255.255
Explanation:
FF-FF-FF-FF-FF-FF can be defined as the layer 2 address broadcast which is often used on ethernet frames as well as help to broadcast all equipment due to the fact broadcast is made possible through Ethernet networks in which the Frames are addressed to reach every computer system on a given LAN segment as far as they are addressed to MAC address FF:FF:FF:FF:FF:FF.
255.255. 255.255 can be seen as the layer 3 address which help to address the exact same hosts because it enables the broadcast address of the zero network which is the local network due to the fact that the IP broadcasts are often used by BOOTP and DHCP clients to find and send requests to their respective servers in which a message sent to a broadcast address may be received by all network-attached hosts.
Therefore the Layer 2 and Layer 3 destination addresses which the message contain are FF-FF-FF-FF-FF-FF and 255.255.255.255
HISTSIZE is the environment variable affects the number of past commands used in the current shell session.
Answer:
Explanation:
With an individual domain name we can upload all the content we want, in a free domain or share domain, upload content in some cases have a limit, for example the size of an image, in an individual domain we can add our brand, in a shared, we can add our brand side to company share those domains, we can have our own email address, practically we have a complete autonomy in our website.
So far the most general and convincing definition is to say that Web Services are the set of applications or technologies with the ability to interoperate on the Web. These technologies exchange data between them in order to offer services.