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diamong [38]
3 years ago
5

What is the volume of a sphere with a radius of 4 cm? Use 3. 14 for pi. Round to the nearest hundredth. 50. 24 cm³ 66. 99 cm³ 20

0. 96 cm³ 267. 95 cm³.
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
4 0

The volume of the sphere is 267. 95 cm³.

<h2>Given </h2>

The radius of the sphere is 4cm.

<h3>What is the volume of sphere?</h3>

The volume of a sphere is the three-dimensional space occupied by a sphere.

The volume of the sphere is determined by the following formula;

\rm Volume = \dfrac{4}{3} \pi r^3

Where r is the radius of the sphere.

Substitute all the values in the formula;

\rm Volume = \dfrac{4}{3} \pi r^3\\\\\rm Volume = \dfrac{4}{3} \times (3.14) \times 4^3\\\\Volume = 4 \times 1.04 \times 64\\\\Volume = 267.95\ cm ^3

Hence, the volume of the sphere is 267. 95 cm³.

To know more about Volume of Sphere click the link given below.

brainly.com/question/369459

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HURRY!!!!! I NEED HELP!!!!!<br>Find Arc MN <br><br><br>A. 20<br><br>b.60<br><br>c.66<br><br>d.120
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We have been given a circle. We are asked to find the measure of arc MN.

We know that the measure of all arcs in a circle is equal to 360 degrees. SO we can set an equation as:

\widehat{MN}+\widehat{NO}+\widehat{OL}+\widehat{LM}=360^{\circ}

Upon substituting our given values, we will get:

\widehat{MN}+110^{\circ}+130^{\circ}+54^{\circ}=360^{\circ}

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Suppose we are sending a digital signal which is a string of 0s and 1s of length five. (Example stringsare 00101, 11000, 10101 a
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0.7738 = 77.38% probability that an incorrect message is received.

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For each bit, there are only two possible outcomes. Either it is corrupted, or it is not. The probability of a bit being corrupted is independent of any other bit. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

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C_{n,x} = \frac{n!}{x!(n-x)!}

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What is the probability that an incorrect message is received?

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