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2 years ago

If P(E) = 0.32, then what are the odds against E?

Mathematics

1 answer:

steposvetlana [31]2 years ago

7 0

Answer:

0.68 : 0.32

Step-by-step explanation:

the probability of all the outcomes of an event is always 1 .

if P(E) = 0.32,

P(E') = 1 - 0.32

= 0.68

N.B that P(E') is the same as P( not E ).

since your answer should be given in the ratio form, as the odds against E ( probability not E : probability E),

P(E') : P(E)

0.68 : 0.32

hope this helps you!

-s.

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Given 4 < x < 9 and 5 - y< 4 , where x and y are integers. Find the maximum value of x-y.

djyliett [7]

Answer:

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2 years ago

A standardized exam's scores are normally distributed. In a recent year, the mean test score was 14901490 and the standard dev

kicyunya [14]

<h2>Answer with explanation:</h2>

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Standard deviation : $\sigma=320$

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5 0

3 years ago

20.

Alik [6]

Answer:

After 3 seconds

Step-by-step explanation:

Given

$h(t) = -16t^2 + 96t$

Required

Seconds to attain maximum height

The maximum of a quadratic function $y = ax^2 + bx + c$ is calculated using:

$x = -\frac{b}{2a}$

So, we have:

$t = -\frac{b}{2a}$

Where:

$a = -16$ and $b = 96$

So:

$t = -\frac{96}{2 * -16}$

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Cancel out negatives

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