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Over [174]
2 years ago
13

If P(E) = 0.32, then what are the odds against E?

Mathematics
1 answer:
steposvetlana [31]2 years ago
7 0

Answer:

0.68 : 0.32

Step-by-step explanation:

the probability of all the outcomes of an event is always 1 .

if P(E) = 0.32,

P(E') = 1 - 0.32

= 0.68

N.B that P(E') is the same as P( not E ).

since your answer should be given in the ratio form, as the odds against E ( probability not E : probability E),

P(E') : P(E)

0.68 : 0.32

hope this helps you!

-s.

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\text{OK. We have}\\a^2=x^2\\2ab=2\cdot x\cdot5\to b=5\\\text{therefore}\ b^2\ \text{must be equal}\ 25=5^2.\\\text{we have:} 24. \text{We have to increase it by 1}\\ \text{Therefore the correct steps are in answer D.}


D.\ Step1\\x^2+10x+24=0\\\\x^2+2\cdot x\cdot5+24=0\\\\x^2+2\cdot x\cdot5+24+1=0+1\\\\Step2\\\\x^2+2\cdot x\cdot5+25=1\\\\x^2+2\cdot x\cdot5+5^2=1\\\\Step3\\\\(x+5)^2=1

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