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1 year ago

If P(E) = 0.32, then what are the odds against E?

Mathematics

1 answer:

steposvetlana [31]1 year ago

7 0

Answer:

0.68 : 0.32

Step-by-step explanation:

the probability of all the outcomes of an event is always 1 .

if P(E) = 0.32,

P(E') = 1 - 0.32

= 0.68

N.B that P(E') is the same as P( not E ).

since your answer should be given in the ratio form, as the odds against E ( probability not E : probability E),

P(E') : P(E)

0.68 : 0.32

hope this helps you!

-s.

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Answer:

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Step-by-step explanation:

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3 years ago

Can someone help me with this?

Anna35 [415]

Answer:

Let 'a' be the first term, 'r' be the common ratio and 'n' be the number of terms

Series = 2+6+18.......= 2+2•3¹+ 2•3².......= 728

Now,

$Sum = \frac{a( {r}^{n} - 1) }{(r - 1)} \\$

So,

$\frac{a( {r}^{n} - 1)}{(r - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{(3 - 1)} = 728 \\ \frac{2( {3}^{n} - 1) }{2} = 728 \\ {3}^{n} - 1 = 728 \\ {3}^{n}=728+1\\ {3}^{n} = 729 \\ {3}^{n} = {3}^{6} \\ \boxed{ n = 6}$

Therefore, number of terms is 6

6 is the right answer.

3 0

2 years ago

sarah uses 2/3 of her supply of cheese to make pizza and 1/9 of her supply of cheese to make lasagna. If Sarah uses 2 1/3 pounds

Oksana_A [137]

Answer: 0.05 cup

Step-by-step explanation:

Divide 2.5 by 10 to find how much is in one of Sarah’s dishes.

This gives you 0.25

Divide 1.6 by 8 to find how much is in one of Amy's dishes.

This gives you 0.2

Now minus 0.2 from 0.25.

This gives you a 0.05 cup

hope this helps

4 0

2 years ago

A rectangular field has an area 28800 sq.meter.its length is twice as long as its width.what is the length of its sides?

AVprozaik [17]

Let
x---------> the length side of rectangle
y---------> the width side of rectangle

we know that
x=2y-----> equation 1
area=x*y-------> 28800=x*y------> equation 2
substitute 1 in 2

28800=[2y]*y-----> 28800=2y²-------> y²=14400------> y=120 m
x=2*y----> x=2*120------> x=240 m

the answer is
the length side of rectangle is 240 m
the width side of rectangle is 120 m

5 0

2 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

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3 years ago