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Over [174]
2 years ago
13

If P(E) = 0.32, then what are the odds against E?

Mathematics
1 answer:
steposvetlana [31]2 years ago
7 0

Answer:

0.68 : 0.32

Step-by-step explanation:

the probability of all the outcomes of an event is always 1 .

if P(E) = 0.32,

P(E') = 1 - 0.32

= 0.68

N.B that P(E') is the same as P( not E ).

since your answer should be given in the ratio form, as the odds against E ( probability not E : probability E),

P(E') : P(E)

0.68 : 0.32

hope this helps you!

-s.

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Answer:

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Step-by-step explanation:

As we know if we have x number of elements we can arrange them in x! ways.

here we have 100 elements so we can arrange them in 100! ways.

Now if we have exactly three parts and 1,2 and 3 are in different parts then let consider 1 goes to part 1, 2 goes to part 2, and 3 goes to part 3. For the remaining 97 elements,  we have three options for each element, thus we can arrange the remaining 97 elements in 3^{97} ways/partitions.

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