All categories

2 years ago

If P(E) = 0.32, then what are the odds against E?

Mathematics

1 answer:

steposvetlana [31]2 years ago

7 0

Answer:

0.68 : 0.32

Step-by-step explanation:

the probability of all the outcomes of an event is always 1 .

if P(E) = 0.32,

P(E') = 1 - 0.32

= 0.68

N.B that P(E') is the same as P( not E ).

since your answer should be given in the ratio form, as the odds against E ( probability not E : probability E),

P(E') : P(E)

0.68 : 0.32

hope this helps you!

-s.

You might be interested in

A colony of ants carried away 14 of your muffins that was 2/3 of all of them how many are left

ZanzabumX [31]

If they took 2/3 away you have 1/3 left. you would have 7 left.

8 0

3 years ago

Read 2 more answers

Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dis

Ronch [10]

<h2>Complete Question: </h2>

Learning Task 1: Identify similar and dissimilar fractions. On your note- book write S if the fractions are similar and D if dissimilar.

1. $\frac{2}{3} $ and $ \frac{1}{3}$

2. $\frac{3}{4} $ and $ \frac{1}4}$

3. $\frac{4}{7} $ and $ \frac{7}{8}$

4. $\frac{2}{5} $ and $ \frac{5}{11}$

5. $\frac{7}{13} $ and $ \frac{7}{9}$

<h2>The answers:</h2>

1. $\frac{2}{3} $ and $ \frac{1}{3}$ - Similar (S)

2. $\frac{3}{4} $ and $ \frac{1}4}$ - Similar (S)

3. $\frac{4}{7} $ and $ \frac{7}{8}$ - Dissimilar (D)

4. $\frac{2}{5} $ and $ \frac{5}{11}$ - Dissimilar (D)

5. $\frac{7}{13} $ and $ \frac{7}{9}$ - Dissimilar (D)

Note:

Similar fractions have the same denominator. i.e. the bottom value of both fractions are the same.
Dissimilar fractions have different value as denominator, i.e. the bottom value of both fractions are not the same.

Thus:

1. $\frac{2}{3} $ and $ \frac{1}{3}$ - They have equal denominator. Both fractions are similar (S).

2. $\frac{3}{4} $ and $ \frac{1}4}$ - They have equal denominator. Both fractions are similar (S).

3. $\frac{4}{7} $ and $ \frac{7}{8}$ - They have equal denominator. Both fractions are dissimilar (D).

4. $\frac{2}{5} $ and $ \frac{5}{11}$ - They have equal denominator. Both fractions are dissimilar (D).

5. $\frac{7}{13} $ and $ \frac{7}{9}$ - They have equal denominator. Both fractions are dissimilar (D).

Therefore, the fractions in 1 and 2 are similar (S) while those in 3, 4, and 5 are dissimilar (D).

Learn more here:

brainly.com/question/22099172

7 0

3 years ago

A radio station had 120 tickets to a concert. They gave away 2 times as many tickets to listeners as to employees. How many tick

enyata [817]

Step-by-step explanation:

If the tickets given to employees = 40

Then tickets given to listeners = 2 x no of employees tickets

= 2 x40 = 80

Total tickets = 40+ 80 = 120

8 0

3 years ago

You have 5 pieces of wood. What is the total length of the wood? 73cm, 1.6m, 2.87m, 325cm and 4.04m

skad [1K]

First, you need to make sure that they're in the same measurement ration

1 m = 100 cm

so, now you have

73 cm + 160 cm + 287 cm + 325 cm + 404 cm

The total length would of all the wood would be be 1249 centimeters or 12.49 meter

8 0

3 years ago

On Halloween, a man presents a child with a bowl containing eight different pieces of candy. He tells her that she may have thre

likoan [24]

Answer:

$56$ choices

Step-by-step explanation:

We know that we'll have to solve this problem with a permutation or a combination, but which one do we use? The answer is a combination because the order in which the child picks the candy does not matter.

To further demonstrate this, imagine I have 4 pieces of candy labeled A, B, C, and D. I could choose A, then C, then B or I could choose C, then B, then A, but in the end, I still have the same pieces, regardless of what order I pick them in. I hope that helps to understand why this problem will be solved with a combination.

Anyways, back to the solving! Remember that the combination formula is

$_nC_r=\frac{n!}{r!(n-r)!}$ , where n is the number of objects in the sample (the number of objects you choose from) and r is the number of objects that are to be chosen.