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RUDIKE [14]
2 years ago
8

Which best describes what happens to sunlight after it passes through the keyhole of a door? It converges into one particular sh

adow region. It spreads out into multiple shadow regions. It bends back toward the door. It scatters back toward the door.
Physics
1 answer:
elena-14-01-66 [18.8K]2 years ago
5 0

Multiple shadow regions can be observed in the wall behind the keyhole of a door. Option B is correct.

<h3>What is diffraction?</h3>

It is a phenomenon that happens when a wave (Light) is passed through a narrow aperture or a sharp edge, the light bends at the edges.

The light bends at the edges because the sharp edges have less diameter than the wavelength of light.

Therefore, multiple shadow regions can be observed in the wall behind the keyhole of a door.

Learn more about diffraction:

brainly.com/question/10303995

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Answer:

surfaces

Explanation:

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3 years ago
One billiard ball is shot east at 2.2m/s. A second, identical billiard ball is shot west at 1.2m/s. The balls have a glancing co
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Answer:

v_{1}=1.886 \frac{m}{s}

β= 57.99 south of east

Explanation:

v_{1}=2.2 \frac{m}{s} \\v_{2}=1.2 \frac{m}{s} \\m_{1}=m_{2}=m\\v_{fx}=1.6 \frac{m}{s} \\v_{fy}=?

Velocity in axis x the two balls come one from east and west

m_{1}*v_{1x}+m_{2}*v_{2x}=m_{1}*v_{fx1}+m_{2}*v_{fx2}\\m*(v_{1x}+v_{2x})=m*(v_{fx1}+v_{fx2})\\v_{fx2}=0\\v_{1x}+v_{2}=v_{f1}+0\\v_{fx1}=2.2 \frac{m}{s}+(1.2\frac{m}{s})\\  v_{fx1}=1 \frac{m}{s} \\

Velocity in axis y initial is zero so:

v_{y1}+v_{y2}=v_{y1f}+v_{y2f}\\v_{y1}=0\\v_{y2}=0\\v_{y1f}+v_{y2f}=0\\v_{y1f}=-v_{y2f}\\v_{y2f}=1.6\frac{m}{s}

v=\sqrt{v_{1fx}^{2}+v_{1fy}^{2}}\\ v=\sqrt{1^{2}+1.6^{2}}\\v=1.886 \frac{m}{s}

Angle is find using:

tan(β)=\frac{v_{fy}}{v_{fx}}

\beta =tan^{-1}*\frac{1.6}{1}=57.99

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~~~hope this helps~~~
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