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statuscvo [17]
3 years ago
15

1.(16 pts.) Find the volume of the solid obtained by revolving the region enclosed by y = xex , y = 0 and x = 1 about the x-axis

.
Physics
1 answer:
MrRa [10]3 years ago
8 0

Answer:

<em>The Volume is 5.018 cubic units</em>

Explanation:

<u>Volume Of A Solid Of Revolution</u>

Let f(x) be a continuous function defined in an interval [a,b], if we take the area enclosed by f(x) between x=a, x=b and revolve it around the x-axis, we get a solid whose volume can be computed as

\displaystyle V=\pi \int_a^bf^2(x)dx

It's called the disk method. There are other available methods to compute the volume.

We have

f(x)=xe^x

And the boundaries defined as x=1, y=0 and revolved around the x-axis. The left endpoint of the integral is easily identified as x=0, because it defines the beginning of the region to revolve. So we need to compute

\displaystyle V=\pi \int_0^1(xe^x)^2dx=\pi \int_0^1x^2e^{2x}dx

We need to first determine the antiderivative

\displaystyle I=\int x^2e^{2x}dx

Let's integrate by parts using the formula

\displaystyle \int u.dv=u.v-\int v.du

We pick u=x^2,\ dv=e^{2x}dx

Then du=2xdx,\ v=\frac{e^{2x}}{2}

Applying by parts:

\displaystyle I=x^2\frac{e^{2x}}{2}-\int 2x\frac{e^{2x}}{2}dx

\displaystyle I=\frac{x^2e^{2x}}{2}-\int xe^{2x}dx

Now we solve

\displaystyle I_1=\int xe^{2x}dx

Making u=x,\ dv=e^{2x}dx

\displaystyle du=dx,\ v=\frac{e^{2x}}{2}

Applying by parts again:

\displaystyle I_1=x\frac{e^{2x}}{2}-\int \frac{e^{2x}}{2}dx

\displaystyle I_1=\frac{xe^{2x}}{2}-\frac{1}{2}\int e^{2x}dx

The last integral is directly computed

\displaystyle \int e^{2x}dx=\frac{e^{2x}}{2}

Replacing every integral computed above

\displaystyle I=\frac{x^2e^{2x}}{2}-\left(\frac{xe^{2x}}{2}-\frac{1}{2}\frac{e^{2x}}{2}\right)

Simplifying

\displaystyle I=\dfrac{\left(2x^2-2x+1\right)\mathrm{e}^{2x}}{4}

Now we compute the definite integral as the volume

V=\pi \left[\dfrac{\left(2(1)^2-2(1)+1\right)\mathrm{e}^{2(1)}-\left(2(0)^2-2(0)+1\right)\mathrm{e}^{2(0)}}{4}\right]

Finally

V=\pi \dfrac{\mathrm{e}^2-1}{4}=5.018

The Volume is 5.018 cubic units

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Consider a sealed 20 cm high electronic box whose base dimensions are 40cm x 40cm placed in a vacuum chamber. The emissivity of
Genrish500 [490]

Answer:

T_{surr}=296.289\ K

In Celsius:

T_{surr}=296.289-273\\T_{surr}=23.289^oC

Explanation:

The formula we are going to use is:

\dot Q_{rad}=\epsilon\sigma A_s(T_s^4-T_{surr}^4)

Where:

ε is the emissivity

σ is the Stefan constant

T_s is the final temperature of surrounding surfaces

T_{surr} is the required temperature

A_s is the are of surrounding surface

Calculating The area:

A_s=(0.4)(0.4)+4(0.4)(0.2)\\A_s=0.48\ m^2

σ= 5.67*10^{-8}\ W/m^2.K^4

ε =0.95

T_s=55+273

T_s=328 K

\dot Q_{rad=100 W

100=0.95(5.67*10^{-8})(0.48)(328^4-T_{surr}^4)\\3867693926=(328^4-T_{surr}^4)\\T_{surr}^4=7706623130\\T_{surr}=296.289\ K

In Celsius:

T_{surr}=296.289-273\\T_{surr}=23.289^oC

8 0
3 years ago
A 0.14-kg baseball is moving at 41 m/s. A 0.058-kg tennis ball is moving at 67 m/s. Which of the two balls has higher kinetic en
lbvjy [14]

Answer:

The kinetic energy of tennis ball is higher than that of baseball.

Explanation:

mass of baseball m_{b} = 0.14 kg

velocity of baseball v_{b} = 41 m/s

mass of tennis ball m_{t}  = 0.058 kg

velocity of tennis ball v_{t}= 67 m/s

To find: the kinetic energy of baseball KE_{b} and tennis ball KE_{t}

We know that the kinetic energy is given by the equation,

KE = \frac{mv^{2}}{2}

the kinetic energy of baseball KE_{b} = \frac{m_{b}v_{b}  ^{2}}{2}

                                                           = \frac{0.14 * 41^{2}}{2}

                                                           = 117.67 J

the kinetic energy of tennis ball KE_{t} = \frac{m_{t}v_{t}  ^{2}}{2}

                                                             = \frac{0.058 * 67^{2}}{2}

                                                             = 130.181 J

Hence KE_{t} > KE_{b}, the kinetic energy of tennis ball is higher than that of baseball

6 0
3 years ago
What is the voltage, V2, in units of Volts, across resistor R2 in the circuit shown below where VS = 4V, R1 = 14 Ohms and R2 = 3
svetlana [45]
<h2>Correct answer:</h2>

\boxed{v_{out}=2,85V}

<h2>Explanation:</h2>

We can use voltage divider to solve this problem that is defined as the passive linear circuit producing an output voltage v_{out} that is a fraction of its input voltage v_{in}. So we can use the formula:

v_{out}=\frac{R_{2}}{R_{1}+R_{2}}v_{in}, \ where \ v_{in}=v_{s}=4V \\ \\ \therefore v_{out}=\frac{35}{14+35}(4) \\ \\ \therefore v_{out}=2,85V

3 0
2 years ago
Microwaves are produced by ​
arlik [135]

Answer:

Microwaves are basically extremely high frequency radio waves, and are made by various types of transmitter. In a mobile phone, they're made by a transmitter chip and an antenna, in a microwave oven they're made by a "magnetron". Their wavelength is usually a couple of centimetres. Stars also give off microwaves.

3 0
3 years ago
Read 2 more answers
What is the potential energy in J of a bungee jumper standing on a 0.109 km bridge that weighs 85 kg?
KatRina [158]

Considering the definition of potential energy, the potential energy of the bungee jumper is 90,889.65 J.

<h3>Potential energy</h3>

Potential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity.

So for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:

Ep= m×g×h

Where:

  • Ep is the potential energy in joules (J).
  • m is the mass in kilograms (kg).
  • h is the height in meters (m).
  • g is the acceleration of fall in m/s² (approximately 9.81 m/s²).

<h3>Potential energy in this case</h3>

In this case, you know:

  • m= 85 kg
  • g= 9.81 m/s²
  • h= 0.109 km= 109 m (being 1 km= 1000 m)

Replacing in the definition of potential energy:

Ep= 85 kg × 9.81 m/s² × 109 m

Solving:

<u><em>Ep= 90,889.65 J</em></u>

Finally, the potential energy of the bungee jumper is 90,889.65 J.

Learn more about potential energy:

brainly.com/question/24933254

brainly.com/question/15896499

brainly.com/question/14456667

#SPJ1

4 0
2 years ago
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