Justin's statement would be the best. In order to change 3/5 into 6/10, both sides would need to be multiplied by 2.
Answer:
Step-by-step explanation:
Assume that the two prisms have bases of equal area.
Then the volume of the rectangular prism is V = (base area)(height).
The volume of the triangular prism is V = (1/3)(base area)(height)
We could compare the two volumes by creating the ratio inequality
(1/3) (base area)(t-height)
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(base area)(r-height)
The triangular prism will have the greater volume for (1/3)((t-height) > r-height.
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Answer:
Step-by-step explanation:
I think the only way you can solve this is to assume that <R means PRT in the given ratio. If I am wrong, I don't think the problem can be solved.
Find <T
Let <T = x
and <PRT = 3x
KLMN is a Parallelagram and therefore two adjacent angles are supplementary.
<PRT + <T = 180 degress
3x + x = 180 degrees
4x = 180
x = 45
So <T = 45
<PRT = 3*45 = 135
If RD is perpendicular to PS then <PDR = 90o
Here's the trick.
RD is also Perpendicular to RT
<MRD + <MRT = 90
<MRT = 180 - 90 - <T
<MRT = 180 - 90 - 45
<MRT = 45
Here comes your answer
=================
<MRD + MRT = 90
<MRD + 45 = 90
<MRD = 45
====================
Note: you must ignore everything to do with the diagram. It is not drawn to scale and the letters are not the same as in the question. The only thing you use is that the figure is a ||gm
Answer:
Step-by-step explanation:
<h3>Q13</h3>
The greater the angle the greater the opposite side
<u>Sides in ascending order:</u>
- AB = 17, AC = 18, BC = 21
<u>Angles in same order</u>
<h3>Q14</h3>
<u>As above, sides in ascending order:</u>
- AB = 15, AC = 16, BC = 17
<u>Angles in same order</u>
<h3>Q15</h3>
<u>Exterior angle equals to sum of non-adjacent interior angles</u>
- 142° = x + 66°
- x = 142° - 66°
- x = 76°
<h3>Q16</h3>
<u>Same subject and isosceles triangle:</u>
- x + x = 158°
- 2x = 158°
- x = 79°
<h3>Q17</h3>
<u>Same subject</u>
- m∠QSR = m∠QPS + m∠PQS
- 2x = x + m∠PQS
- m∠PQS = 2x - x
- m∠PQS = x
ΔPQS has two angles with the measure of x, hence their opposite sides are congruent and the triangle is isosceles
