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bekas [8.4K]
2 years ago
5

How to factor this expression: x^2-9?

Mathematics
1 answer:
Lena [83]2 years ago
7 0

Answer:

(x+3)(x-3)

Step-by-step explanation:

rewrite "9" as 3^2

so it is x^2-3^2

You use the difference of squares: a^2-b^2=(a+b)(a-b)

apply it: (x+3)(x-3)

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Step-by-step explanation:

x+8000=y

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7 0
3 years ago
The volume of a cube is 1000cm3. Find:
Gala2k [10]
Length of one edge is 10cm
And the surface area is 600cm2
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3 years ago
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If cells are: a1=90, a2=85, a3=80, a4=75, and a5=75. what will be your formula if you are going to get the average?
swat32
The average can be given by the following formula:
 Average = (a1 + a2 + a3 + a4 + a5) / (5).
 Equivalently.
 Average = (ai) / (i).
 Where,
 i = 1,2,3,4, ..., n
 Substituting
 Average = (90 + 85 + 80 + 75 + 75) / (5).
 Average = 81
 answer:
 Average = (a1 + a2 + a3 + a4 + a5) / (5).
 or
 Average = (ai) / (i).
 Where,
 i = 1,2,3,4, ..., n
8 0
3 years ago
A metallurgist has one alloy containing 32% copper and another containing 65% copper. How many pounds of each alloy must he use
kompoz [17]

Answer:

<h2>30.67 pounds of 32% copper alloy and 10.33 pounds of 65% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 32% copper and the second alloy contains 65% alloy.

We wish to make 44 pounds of a third alloy containing 42% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 44\text{ }pounds=x+y        -(i)

      Total weight of copper = 42\%\text{ of 44 pounds = }32\%\text{ of }x\text{ pounds + }65\%\text{ of }y\text{ pounds }

       \dfrac{42\times 44}{100}=\dfrac{32x}{100}+\dfrac{65y}{100}\\\\ 32x+65y=1848        -(ii)

       Subtracting 32 times first equation from second equation,

32x+65y-32x-32y=1848-32\times44\\33y=440\\y=13.333\text{ }pounds \\x=30.667\text{ }pounds

∴ 30.67 pounds of first alloy and 13.33 pounds of second alloy were used.

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$348.38 so the answer is  d.
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