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Anit [1.1K]
3 years ago
9

Critical Thinking

Chemistry
1 answer:
goldenfox [79]3 years ago
6 0

Answer:

we are given that

Student converts grams to milligrams by multiplying by the conversion factor 1g/1000 mg.

we have been asked to find Is the student performing this calculation correctly?

Suppose you have x grams of  something and convert it into mg as follows:

As we know that

So we can write

mg

It mean that conversion factor is

It mean student doesn't performed the calculations correctly.

Explanation:

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Choose the reaction that represents the combustion of C6H12O2.
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The answer to your question is:  letter D

Explanation:

In a combustion reaction, the reactants are always a molecule with Carbon that reacts with oxygen and the products are carbon dioxide and water.

According to the explanation, the only possible solution is:

a) C₆H₁₂O₂(l) ⇒ 6 C(s) + 6 H₂(g) + O₂(g)

b) Mg(s) + C₆H₁₂O₂(l) ⇒ MgC₆H₁₂O₂(aq)

c) 6 C(s) + 6 H₂(g) + O₂(g) ⇒ C₆H₁₂O₂(l)

d) C₆H₁₂O₂(l) + 8 O₂(g) ⇒ 6 CO₂(g) + 6 H₂O(g)

e) None of the above represent the combustion of C₆H₁₂O₂.

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For each of the following sublevels, give the n and l values and the number of orbitals: (a) 6g; (b) 4s; (c) 3d.
olya-2409 [2.1K]

Answer:

(a) 6g. Shell 6, n = 6. Subshell g, l = 4. Number of orbitals in sublevel = 9

(b) 4s. Shell 4, n = 4. Subshell s, l = 0. Number of orbitals in sublevel = 1

(c) 3d. Shell 3, n = 3. Subshell d, l = 2. Number of orbitals in sublevel = 5

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n, n = 1, 2, 3...

2. Subshell number, 0 ≤ l ≤ n − 1, orbital s - 0, p - 1, d - 2, f - 3

3. Orbital energy shift, -l ≤ ml ≤ l

4. Spin, either -1/2 or +1/2

So,

(a) 6g. Shell 6, n = 6. Subshell g, l = 4. Number of orbitals in sublevel = 2l+1 = 9

(b) 4s. Shell 4, n = 4. Subshell s, l = 0. Number of orbitals in sublevel = 2l+1 = 1

(c) 3d. Shell 3, n = 3. Subshell d, l = 2. Number of orbitals in sublevel = 2l+1 = 5

4 0
4 years ago
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