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3 years ago

Can someone help me determine the name of the formula

Chemistry

1 answer:

kaheart [24]3 years ago

8 0

CrP is Chromium Phosphide

SnI2 is Tin(II) Iodine

Sni4 is Tin

SnS is Tin(II) Sulfide

SnS2 is Tin Sulfide

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What are some of thr similarties of physical changes and chemical changes?

Marysya12 [62]

The similarities of physical and chemical changes is that both of those changes change the way the object looks by it's physical appearance. Also they use a type of element to change that object.

5 0

3 years ago

Where is most of the mass found in an atom

IgorLugansk [536]

massive livand that sarah or someone is how u do it

7 0

3 years ago

Read 2 more answers

What are the 5 ways to identify if a chemical reaction happened?

vlada-n [284]

Answer:

a new substance is formed, if heat is formed, color change, the evolution of gas, and bubbles or fizzing

7 0

3 years ago

When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H

Debora [2.8K]

Answer:

$Y=58.15\%$

Explanation:

Hello,

For the given chemical reaction:

$Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)$

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

$n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3$

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

$n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol Al_2S_3$

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

$m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3$

Finally, we compute the percent yield with the obtained 2.10 g:

$Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%$

Best regards.

7 0

3 years ago

A sample of a substance that has a density of 0.824 g/mL has a mass of 0.451g. Calculate the volume of the sample.

Allushta [10]

Density can be calculated using the following rule:
density=mass/volume
therefore,
volume=mass/density

we have mass=0.451g and density=0.824g/ml
substituting in the above equation, we can calculate the volume as follows:
volume = 0.451/0.824 = 0.547 ml

8 0

4 years ago